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javascript - 在 React-Native 中切换屏幕时如何保存数据?

转载 作者:行者123 更新时间:2023-12-02 21:32:56 25 4
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在我的代码中,我有一个页面显示从数据库检索的元素列表。不过,我还添加了一个页面,允许用户选择多个过滤器。

我有两个问题:

  1. 离开页面后我必须保存数据(它必须保留在那里)
  2. 我必须将数据传输回元素列表。

我认为通过给过滤器屏幕一个来自前一个屏幕的变量,它可以将数据保存在那里,但它似乎不起作用。

你有什么指示我应该做什么吗?

import React from 'react'
import { SafeAreaView, View, Text } from 'react-native'
import {generalStyles} from '@gym-app/styles/general'
import { useTranslation } from 'react-i18next'
import { TouchableOpacity } from 'react-native-gesture-handler';

export default function ExerciseSelectorScreen({navigation}) {

const {t} = useTranslation();
var filterProps = {};

return (
<SafeAreaView style={generalStyles.contentContainer}>
<View style={[generalStyles.contentContainer]}>
<Text>{JSON.stringify(filterProps)}</Text>
<View style={{flexDirection: 'row', justifyContent: 'space-between', alignItems: 'center'}}>
<Text style={generalStyles.title}>{ t('exercise.exercises') }</Text>
<TouchableOpacity onPress={() => {navigation.navigate('Exercises Filter', {filterProps: filterProps})}} style={{padding: 10, backgroundColor: '#ffb623'}}>
<Text style={{fontSize: 20, fontWeight: 'bold'}}>{t('general.filters').toUpperCase()}</Text>
</TouchableOpacity>
</View>
</View>
</SafeAreaView>
)
}

import React, { useState, useEffect } from 'react'
import { View, SafeAreaView, Text, ScrollView, StyleSheet } from 'react-native'
import {generalStyles} from '@gym-app/styles/general'
import { useTranslation } from 'react-i18next'
import persistent from '@gym-app/database/persistent'
import tdb from '@gym-app/translation/object'
import CheckboxGroup from '../../components/workout/exercises/filters/CheckboxGroup'
import { useRoute } from '@react-navigation/native';

export default function ExercisesFilterScreen() {

const {t} = useTranslation();
const route = useRoute();
var filterProps = route.params.filterProps;
const [equipments, setEquipments] = useState({});
const [selectedEquipments, setSelectedEquipments] = useState({});
const [order, setOrder] = useState('');
const [machine, setMachine] = useState('yes');

useEffect(()=> {
if (Object.values(equipments).length == 0) {
persistent.transaction(tx => {
tx.executeSql(
"SELECT * FROM equipment",
[],
(t, s) => {
var transEquip = {};
Object.values(s.rows._array).map((equipment) => {
transEquip[equipment.id] = tdb(equipment, 'name')
})
setEquipments(transEquip);
},
(t, e) => {
console.log(e);
}
);
});
}
},[equipments])

useEffect(() => {
filterProps.selectedEquipments = selectedEquipments;
filterProps.order = order;
filterProps.machine = machine;
})

return (
<SafeAreaView style={{flex: 1}}>
<ScrollView style={[generalStyles.contentContainer, {flex: 1, backgroundColor: '#ffb623'}]}>
<Text style={{fontSize: 30, fontWeight: 'bold', color: '#ffffff', textAlign: 'center'}}>{t('general.filters').toUpperCase()}</Text>
<View style={{marginTop: 10}}>
<CheckboxGroup
title={t('exercise.availableEquipment')}
selected={selectedEquipments}
select={setSelectedEquipments}
multi={true}
options={
equipments
}
/>
<CheckboxGroup
title={t('exercise.order')}
selected={order}
select={setOrder}
multi={false}
options={
{
"asc": t('exercise.easyToHard'),
"desc": t('exercise.hardToEasy'),
}
}
undefined={'allow'}
/>
<CheckboxGroup
title={t('exercise.machines')}
selected={machine}
select={setMachine}
multi={false}
options={
{
"yes": t('exercise.machine.yes'),
"no": t('exercise.machine.no'),
"only": t('exercise.machine.only')
}
}
/>
</View>
</ScrollView>
</SafeAreaView>
)
}

const styles = StyleSheet.create({
optionTitle: {
marginBottom: 6,
fontSize: 24,
fontWeight: 'bold',
color: '#ffffff',
textAlign: 'left'
}
})

最佳答案

使用“全局变量”的最佳方式。通过使用它,您可以在多个屏幕上访问数据并在平面列表中重新渲染。 (Redux也是解决方案,但初始很难理解)。您可以在构造函数中初始化全局变量,并可以更新屏幕中的任何位置。这是您可以了解react-native中的全局变量的链接。 https://aboutreact.com/react-native-global-scope-variables/

关于javascript - 在 React-Native 中切换屏幕时如何保存数据?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/60573922/

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