PHP 验证一堆复选框失败

Question

表单

echo '<form action="formProcess.php" method="post">';
echo    '<input type="checkbox" name="country[]" value="US">';
echo    '<input type="checkbox" name="country[]" value="UK">';
echo    '<input type="checkbox" name="country[]" value="SE">';
echo    '<input type="checkbox" name="country[]" value="CA">';
echo    '<input type="submit" name="Submit" value="Submit">';
echo '</form>';

?>

formProcess.php

<?php


if (isset($_POST['country'])) {
    echo 'Set <br>';
    if (check($_POST['country'])){
        echo 'Country OK<br>';
    } else {
        echo 'Country Faulty<br>';
    }

} else {
    echo 'Not Set';
}

function check($colors) { // This function is where I fail
    global $countries;

    foreach($colors as $country) {
        echo "You selected: $country <br>";
        if (array_key_exists($country,$countries)) {
            return true;
        } else {
            return false;
        }
    }
}
?>

我正在尝试验证一堆复选框，但函数内的 return 部分出错了。

问题是，即使我选择多个复选框，我也只能输出一个值。问题出在函数的return 中。这是如何正确完成的？

输出

Set

You selected: US // Outputs only one even when more are selected.

Country OK

国家数组

$countries = array (
"US" => "United States Of America",
"GB" => "United Kingdom",
"CA" => "Canada"
// a lot more removed for this question
}

Answer 1

您可以使用选定的复选框创建一个数组并返回该数组。

function check($colors) { 
    global $countries;
    $checkedCountries = array();
    foreach($colors as $country) {
        echo "You selected: $country <br>";
        if (array_key_exists($country,$countries)) {
            $checkedCountries[] = $country;
            echo $country . "<br />";
        }
    }
    if(count($checkedCountries) > 0)
    return true;
    else  
    return false;
}