c - 将 void 指针指向 char 指针

Question

我有两个指针。一个带有字符串“test”的 char 指针和一个 void 指针。我试图让pointer指向string的地址。这是我的代码:

#include <stdio.h>

int main(){
    void *pointer = NULL;
    char *string = "test";
    *(char*)pointer = &string;

    printf("The string address: %p\n", string);
    printf("The string: %s\n", string);
    printf("The pointer address: %p\n", pointer);
    printf("The pointer points to: %p", *(char*)pointer);

    return 0;
}

当我将第 6 行的 pointer 设置为等于 string 的地址时，我得到 makes integer frompointer without a Cast。我该如何做到这一点？

编辑:我打印了错误的地址。我的意思是 printf 行看起来像这样:

#include <stdio.h>

int main(){
    void *pointer = NULL;
    char *string = "test";
    pointer = &string;

    printf("The string address: %p\n", &string);
    printf("The string: %s\n", string);
    printf("The pointer address: %p\n", &pointer);
    printf("The pointer points to: %p", pointer);

    return 0;
}

现在可以正确打印出以下内容:

The string address: 0028FF18
The string: test
The pointer address: 0028FF1C
The pointer points to: 0028FF18

因此，string和pointer是单独的指针，pointer指向string。

Answer 1

为什么不简单地做

#include <stdio.h>

int main(){
    void *pointer = NULL;
    char *string = "test";
    pointer = &string; // point to the address of string
    printf("The string address: %p\n", string);
    printf("The string: %s\n", string);
    printf("The pointer address: %p\n", pointer);
    printf("The pointer points to: %p\n", (char*)(*(char**)(pointer)));

    return 0;
}