javascript - 以字符串数组形式返回两个日期之间的月数

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//So I have and array of months
 const months = [
     'January',
     'February',
     'March',
     'April',
     'May',
     'June',
     'July',
     'August',
     'September',
     'October',
     'November',
     'December'];

// If the input is startDate: 1-1-2019 & endDate: 3-15-21
// It should return an array like so:

const monthsBetweenDates = [January,February,March,April,May,June,July,August, September, October, November,December, January,February,March,April,May,June,July,August, September, October, November, December, January, Feb, March];

// The returned/new array should have all months between the start and end date above in Order, duplicated needed in order as well.

非常感谢您的帮助和时间。如果您还有任何疑问，请告诉我。

Answer 1

简单的算术解决方案

<小时/>

考虑到目标，我想说用基本数学来解决任务比处理 Date 类型更有意义。

您所需要的是:

• destructure开始和结束日期的日期字符串 (m-d-yyyy)，分为开始/结束月份和年份 (mStart、yStart、mEnd, yEnd):

const [mStart, , yStart] = start.split('-'),
      [mEnd, , yEnd] = end.split('-') 

• 计算期间的总长度(以月为单位，包括开始和结束)

12*(yEnd-yStart)+(mEnd-mStart)+1}

• 返回array相应的长度，其中每一项都将从源 month 数组中取出，旋转移动一个位置:

months[(mStart-1+i)%months.length]

<小时/>

您可以在下面找到完整的演示:

const startDate = '1-1-2019',
      endDate = '3-15-2021',
     
      monthsBetweenDates = (start,end) => {
        const months = ['January','February','March','April','May','June','July','August','September','October','November','December'],
              [mStart, , yStart] = start.split('-'),
              [mEnd, , yEnd] = end.split('-')             
        return Array.from(
          {length: 12*(yEnd-yStart)+(mEnd-mStart)+1},
          (_,i) => months[(mStart-1+i)%months.length]
        )
      }
      
console.log(monthsBetweenDates(startDate,endDate))

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