javascript - 期望在箭头函数错误的末尾返回一个值

Question

我有这个错误 Expected to return a value at the end of arrow function consistent-return。我不确定如何防止这种情况。

我试图在屏幕尺寸低于 1060 像素时停止 Swiper 轮播

    import Swiper from 'swiper';

    export default function () {
      let articlesGalleryCarousel;

      const doSomething = () => {
        const enableSwiper = () => {
          articlesGalleryCarousel = new Swiper('.js-swiper-container', {
            loop: true,
            slidesPerView: 'auto',
            centeredSlides: true,
            a11y: true,
            keyboardControl: true,
            grabCursor: true,
            pagination: '.swiper-pagination',
            paginationClickable: true,
            navigation: {
              nextEl: '.carousel-button--prev',
              prevEl: '.carousel-button--next',
            },
          });
        };

        const breakpoint = window.matchMedia('(max-width:1060px)');

        const breakpointChecker = () => {
          if (breakpoint.matches === true) {
            if (articlesGalleryCarousel !== undefined) articlesGalleryCarousel.destroy(true, true);
          } else if (breakpoint.matches === false) {
            return enableSwiper();
          }
        };

        breakpoint.addListener(breakpointChecker);

        breakpointChecker();
      };
      return doSomething;
    }

Answer 1

这是一个 ESLint consistent-return警告。

"This rule requires return statements to either always or never specify values"

在第一个 IF 语句的情况下，您的函数“breakpointChecker”没有返回任何内容。