Scala 异步/回调代码重写

Question

应该通过检查用户、用户是否处于事件状态以及更新上次登录日期时间之后的简单代码。

  def authenticate() = Action.async { implicit request => 
    loginForm.bindFromRequest.fold(
        errors => Future.successful(BadRequest(views.html.logon(errors))),
        usersData =>{
           val cursor =  this.collection.find(BSONDocument("name" -> usersData._1)).one[Account].map(_.filter(p=>p.password == hashedPass(usersData._2, usersData._1)))
           cursor.flatMap(p => p match {
               case None => Future.successful(BadRequest(views.html.logon(loginForm.withGlobalError("user/pass incorect!!!"))))
               case Some(user) => {
                 if(!user.active) 
                   Future.successful(BadRequest(views.html.logon(loginForm.withGlobalError("inactive!!!"))))
                 else collection.update(BSONDocument("_id" -> user.id), 
                          BSONDocument("$set" -> 
                          BSONDocument("lastLogin" -> BSONDateTime(new org.joda.time.DateTime().getMillis()))))
                          .flatMap(x => gotoLoginSucceeded(user.id.stringify))

               }
               })
            })
  }  

如何将其重写为更少的 flatMap/map 意大利面？

另一种解决方案

def authenticate() = AsyncStack { implicit request => 
loginForm.bindFromRequest.fold(
    errors => Future.successful(BadRequest(views.html.logon(errors))),
    usersData =>{
      for{
        user <- this.collection.find(BSONDocument("name" -> usersData._1)).one[Account].map(_.filter(p=>p.password == hashedPass(usersData._2, usersData._1)))
        update <- {
         lazy val update = collection.update(BSONDocument("_id" -> user.get.id), 
         BSONDocument("$set" -> 
         BSONDocument("lastLogin" -> BSONDateTime(new org.joda.time.DateTime().getMillis()))))
         update
        }
        result <- {
         lazy val result = gotoLoginSucceeded(user.get.id.stringify)
         result
        } 
      } yield
        if(user.isEmpty) BadRequest(views.html.logon(loginForm.withGlobalError("login\pass mismatch")))
        else if(!user.get.active) BadRequest(views.html.logon(loginForm.withGlobalError("inactive")))
        else if(update.err.isEmpty) result
        else  InternalServerError(views.html.logon(loginForm.withGlobalError("server error")))
        })

}

Answer 1

我可能会将代码重构为如下所示:

def authenticate() = Action.async { implicit request => 
  loginForm.bindFromRequest.fold(
     hasErrors = displayFormWithErrors,
     success = loginUser)
}  

private def displayFormWithErrors[T](errors:Form[T]) = 
  Future.successful(BadRequest(views.html.logon(errors)))

private def loginUser(userData:(String, String)) = {
  val (username, password) = userData

  findUser(username, password)
    .flatMap {
      case None => 
        showLoginFormWithError("user/pass incorect!!!")
      case Some(user) if (!user.active) =>
        showLoginFormWithError("inactive!!!")
      case Some(user) =>
        updateUserAndRedirect(user)
  }
}

private def findUser(username:String, password:String) =
  this.collection
    .find(BSONDocument("name" -> username))
    .one[Account]
    .map(_.filter(_.password == hashedPass(password, username)))

private def showLoginFormWithError(error:String) = 
  Future.successful(BadRequest(
    views.html.logon(loginForm.withGlobalError(error))))

private def updateUserAndRedirect(user:Account) = 
  updateLastLogin(user)
    .flatMap(_ => gotoLoginSucceeded(user.id.stringify))

private def updateLastLogin(user:Account) = 
  collection
    .update(BSONDocument("_id" -> user.id), 
              BSONDocument("$set" -> 
              BSONDocument("lastLogin" -> 
              BSONDateTime(new JodaDateTime().getMillis()))))