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django - 如何使用 Django 连接两个表而不使用原始 sql?

转载 作者:行者123 更新时间:2023-12-02 19:53:22 24 4
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是否可以使用 Django 的 ORM 以编程方式连接两个表?我有两个模型:主题和投票。在我的模板上,我有一个主题列表,用户可以像 Reddit 一样向上/向下投票。除了对结果进行排序之外,一切都按预期进行。我无法弄清楚如何根据分数(每个对象的投票数之和)对对象​​列表进行排序。我可以毫无问题地从 postgres 检索所需的数据:

select i.id, i.title, i.date_created, s.object_id, s.vote, Sum(vote) 
from topic_topic i, votes s
where i.id = s.object_id
group by 1, 2, 3, 4, 5
order by sum DESC;

它返回所需的结果:

id | title  |         date_created          | object_id | vote | sum 

11 | sdfg | 2012-06-04 23:30:17.805671-07 | 11 | 1 | 2

1 | test | 2012-05-13 17:03:24.206092-07 | 1 | 1 | 2

3 | asdf | 2012-05-13 19:23:15.059135-07 | 3 | 1 | 2

2 | adsf | 2012-05-13 19:21:34.180905-07 | 2 | 1 | 2

12 | 11 | 2012-06-04 23:30:54.759158-07 | 12 | 1 | 2

9 | asfd | 2012-05-24 00:26:26.705843-07 | 9 | -1 | -1

4 | asdf | 2012-05-14 19:59:52.450693-07 | 4 | -1 | -2

问题是,我不确定如何将其作为查询集检索。目前我正在使用以下内容来显示对象:

topic_list = Topic.objects.all()

除了排序顺序之外,一切都按照我想要的方式显示。我希望首先显示最高分。

我已经看过的资源: https://docs.djangoproject.com/en/dev/topics/db/managers/#adding-extra-manager-methods
How to query as GROUP BY in django?

还有更多,但作为新用户,反垃圾邮件阻止我添加它们。

我尝试过的事情:

链:

listed_links = list(chain(topic, score))

不幸的是,如果我尝试添加排序值,就会失败。

组合对象列表:

topic = Topic.objects.all().values_list('user','id', 'title','slug', 'date_created', 'date_updated',)

score = Vote.objects.values('object_id').annotate(total=Sum('vote')).order_by('-total')

results = []

for topic in topic:
results.append(topic)

for score in score:
results.append(topic)

这导致我想要的所有对象都出现在一个列表中,但我无法弄清楚如何将 topic.id 链接到 score.object_id

我也尝试过插入原始 SQL,但我觉得我做得不正确,并且可能导致第三方 SQL 注入(inject)。

我很乐意将这一结果分享给 django-voting 项目。就像我说的,一切都按预期进行,除了我不知道如何按分数降序排序。

============投票==========================

from django.contrib.contenttypes import generic

from django.contrib.contenttypes.models import ContentType

from django.contrib.auth.models import User

from django.db import models

from voting.managers import VoteManager

from voting.VotedObjectsManager import VotedObjectsManager

SCORES = (
(+1, u'+1'),
(-1, u'-1'),
)

class Vote(models.Model):

"""
A vote on an object by a User.
"""

user = models.ForeignKey(User)

content_type = models.ForeignKey(ContentType)

object_id = models.PositiveIntegerField()

object = generic.GenericForeignKey('content_type', 'object_id')

vote = models.SmallIntegerField(choices=SCORES)

objects = VoteManager()


class Meta:
db_table = 'votes'
# One vote per user per object
unique_together = (('user', 'content_type', 'object_id'),)

def __unicode__(self):
return u'%s: %s on %s' % (self.user, self.vote, self.object)

def is_upvote(self):
return self.vote == 1

def is_downvote(self):
return self.vote == -1

============主题模型==========================

from django.db import models

from datetime import datetime

from tinymce import models as tinymce_models

from django.forms import ModelForm

from django.template.defaultfilters import slugify

from tagging.fields import TagField

from tagging.models import Tag

from django.contrib.auth.models import User

from django.utils.translation import ugettext_lazy as _

from django.contrib.contenttypes.models import ContentType

from django.contrib.contenttypes import generic

from django.core import urlresolvers

class Topic(models.Model):

title = models.CharField(max_length=50)

slug = models.SlugField(max_length=50, editable=False)

topic = tinymce_models.HTMLField()

date_created = models.DateTimeField(editable=False)

date_updated = models.DateTimeField(editable=False)

tags = TagField()


def set_tags(self, tags):
Tag.objects.update_tags(self, tags)

def __unicode__(self):
return self.tags

def __unicode__(self):
return self.id

def __unicode__(self):
return self.title

最佳答案

我能够使用此处描述的补丁找到解决方案:

http://code.google.com/p/django-voting/issues/detail?id=10

不同之处在于我提取了以下几行:

    def select_score(self):
""" Add vote scores for objects in resoultset """
from django.contrib.contenttypes.models import ContentType
model_type = ContentType.objects.get_for_model(self.model)
table_name = self.model._meta.db_table
print type(model_type)
print model_type.id
return self.extra(select={'score': 'SELECT SUM(vote) FROM votes WHERE content_type_id=%i AND object_id=%s.id' % (int(model_type.id), table_name)})

并将它们添加到 voting/managers.py 文件中,如下所示:

class VoteManager(models.Manager):
def get_score(self, obj):
"""
Get a dictionary containing the total score for ``obj`` and
the number of votes it's received.
"""
ctype = ContentType.objects.get_for_model(obj)
result = self.filter(object_id=obj._get_pk_val(),
content_type=ctype).extra(
select={
'score': 'COALESCE(SUM(vote), 0)',
'num_votes': 'COALESCE(COUNT(vote), 0)',
}).values_list('score', 'num_votes')[0]

return {
'score': int(result[0]),
'num_votes': int(result[1]),
}

然后在我的topic.views.py中我添加了以下内容:

from voting.managers import VoteManager
def index(request):
queryset = Topic.objects.select_score().order_by('-score')
paginator = Paginator(queryset, 3) # Show 25 contacts per page

page = request.GET.get('page')
try:
topic_list = paginator.page(page)
except PageNotAnInteger:
# If page is not an integer, deliver first page.
topic_list = paginator.page(1)
except EmptyPage:
#If page is out of range (e.g. 9999), deliver last page of results.
topic_list = paginator.page(paginator.num_pages)

c = Context({
'topic_list': topic_list,
'request': request
})
return render_to_response('idea/index.html', c, context_instance=RequestContext(request))

最后,在我的 index.html 中,我添加了以下几行,与为用户提供的原始示例略有不同:

{% load voting_tags %}
{% votes_by_user user on topic_list as vote_dict %}
{% scores_for_objects topic_list as score_dict %}

<table id="voting_table" class="list">
<tbody>
{% for link in topic_list %}
<td class="vote">

{% dict_entry_for_item link from vote_dict as vote %}
{% dict_entry_for_item link from score_dict as score %}

<div>
<form class="linkvote" id="linkup{{ link.id }}"{% if vote and vote.is_upvote %} action="{% url link_vote object_id=link.id, direction="clear" %}"{% else %} action="{% url link_vote object_id=link.id, direction="up" %}"{% endif %} method="POST">
<input type="image" id="linkuparrow{{ link.id }}" src="{{ STATIC_URL }}images/aup{% if vote and vote.is_upvote %}mod{% else %}grey{% endif %}.png">
{% csrf_token %}
<input type="hidden" name="next" value="{{ request.get_full_path }}"/>
{% else %}

</form>

<div id="link_score">{{ score.score|default:0 }}</div>

<form class="linkvote" id="linkdown{{ link.id }}" {% if vote and vote.is_downvote %} action="{% url link_vote object_id=link.id, direction="clear" %}"{% else %} action="{% url link_vote object_id=link.id, direction="down" %}"{% endif %} method="POST">
{% csrf_token %}
<input type="image" id="linkdownarrow{{ link.id }}" src="{{ STATIC_URL }}images/adown{% if vote and vote.is_downvote %}mod{% else %}grey{% endif %}.png">
<input type="hidden" name="next" value="{{ request.get_full_path }}"/>

</td>
<td class="item">
<a id="link_title" href="{{ link.id }}">{{ link.title|escape }}</a></h2>
<p class="details">
<span class="score" id="linkscore{{ link.id }}"
title="after {{ score.num_votes|default:0 }} vote{{ score.num_votes|default:0|pluralize }}">
</span>
posted {{ link.date_created|timesince }} ago by
<span class="user"><a href="../users/{{ link.user.id }}/">{{ link.owner|escape }}</a></span>
{% get_comment_count for link as comment_count %}
<span id="comment_score" class="comment_details"> {{ comment_count }} comment{{ comment_count|pluralize }}</span>
</p>
</td>
</tr>{% endfor %}
</tbody>
<td>
<div id="paginator" class="pagination">
<span class="step-links">
{% if topic_list.has_previous %}
<a href="?page={{ topic_list.previous_page_number }}">previous</a>
{% endif %}
{% if topic_list.has_next %}
<a href="?page={{ topic_list.next_page_number }}">next</a>
{% endif %}
</span>
</div>
</td>
</table>

编辑

我差点忘了!如果您希望列表按 2,1,0,-1,-2 等顺序排序,请确保在提交您正在创建的任何对象时设置投票对象值。下面的示例来 self 的 topic.views.py

def submit_topic(request):

if request.method == 'POST':
post_topic = PosttopicForm(request.POST)
owner = request.user
if post_topic.is_valid():
topic = post_topic.save(commit=False)
topic.owner = request.user
topic.save()
vote = Vote(vote='0', user = request.user, content_type_id=10, object_id=topic.pk)
vote.save()
url = reverse('topic', args=[topic.pk, topic.slug])
return HttpResponseRedirect(url)
else:
post_topic = PosttopicForm()

c = Context({
'form': post_topic,
'user': request.user,
'request': request,

})

return render_to_response('topic/submit.html', c, context_instance=RequestContext(request))

我真的希望这对其他人有帮助。抱歉没有早点发布解决方案。希望有人可以通过从 VoteManager 中删除 SQL 来改进这一点,但我需要继续前进。

关于django - 如何使用 Django 连接两个表而不使用原始 sql?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/11073698/

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