python-3.x - 如何使用 BeautifulSoup 解析嵌套标签

Question

HTML 代码

<a href="1.co">1<a href="2.co">2</a></a>

我尝试递归调用 BS 获取第一个标签的“内容”，但 BS 失败

        if hasattr(markup, 'read'):        # It's a file-type object.
>           markup = markup.read()
E           TypeError: 'NoneType' object is not callable

Python代码

from bs4 import BeautifulSoup
from bs4 import SoupStrainer


def parse(text):
    soup = BeautifulSoup(text, parse_only=SoupStrainer(['a']), features="html.parser")
    for tag in soup:
        if tag.name == "a" and tag.has_attr("href"):
            print(tag["href"])
        if hasattr(tag, "contents"):
            for text in tag.contents:
                parse(text)

if __name__ == '__main__':
    parse("""<a href="2.co">2<a href="3.co">3</a></a>""")

Answer 1

只需执行 find_all('a')

from bs4 import BeautifulSoup
data='''<a href="1.co">1<a href="2.co">2</a></a>'''
soup=BeautifulSoup(data,'html.parser')
for item in soup.find_all('a',href=True):
    print(item['href'])