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python - 值错误: Filename must be a string while uploading file to s3 bucket

转载 作者:行者123 更新时间:2023-12-02 19:42:34 25 4
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我正在 postman 中发送一个 excel 文件作为请求,并且需要将其上传到 s3 。我通过请求访问该文件并将其发送到 s3。

@api_view(['POST'])
def excel_upload(request):
print("request", request)
excel_file = request.FILES['file']
print("excel_file", excel_file) // this prints the name of the excel file i am sending in request
upload_to_aws(excel_file,'X1excelsheets','s3_file_name')

这里是上传文件到s3的函数。

def upload_to_aws(local_file, bucket, s3_file):
s3 = boto3.client('s3', aws_access_key_id=ACCESS_KEY,
aws_secret_access_key=SECRET_KEY)

try:
s3.upload_file(local_file, bucket, s3_file)
print("Upload Successful")
return True
except FileNotFoundError:
print("The file was not found")
return False
except NoCredentialsError:
print("Credentials not available")
return False


uploaded = upload_to_aws('local_file', 'bucket_name', 's3_file_name')

我正在尝试使用这个特定的帖子

https://medium.com/bilesanmiahmad/how-to-upload-a-file-to-amazon-s3-in-python-68757a1867c6

把事情做好。错误:ValueError:文件名必须是字符串

最佳答案

我用 AWSCLI 进行了配置

S3_BUCKET_NAME = 'YOUR_BUCKET'

s3 = boto3.client('s3')
with open(file, 'rb') as f:
s3.upload_fileobj(f, S3_BUCKET_NAME, file)

我遇到了同样的错误,所以我只是使用 upload_fileobj 而不是 upload_file。这对我来说效果很好,你可以尝试一下。

关于python - 值错误: Filename must be a string while uploading file to s3 bucket,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/59891320/

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