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excel - 如何使用另一列中的值的引用来增加一列中的值

转载 作者:行者123 更新时间:2023-12-02 19:31:02 24 4
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我想在 C 列和 D 列中添加 n 个单元格,其中 n 是 B 列中的值

我的代码是:

Sub mycode()
Dim lastrow1 As Long
lastrow1 = Range("A" & Rows.Count).End(xlUp).Row

Dim lastrow2 As Long
lastrow2 = Range("C" & Rows.Count).End(xlUp).Row

For h = 2 To lastrow1
For i = 2 To lastrow2
If Sheet1.Cells(h, 1).Value = Sheet1.Cells(i, 3).Value Then
P = 10
t = i + 1
For j = 1 To Cells(i, 2).Value
Sheet1.Cells(t, 3).Insert shift:=xlDown
Sheet1.Cells(t, 4).Insert shift:=xlDown
Sheet1.Cells(t, 3).Value = Sheet1.Cells(i, 3).Value
Sheet1.Cells(t, 4).Value = Sheet1.Cells(i, 4).Value + P
P = P + 10
t = t + 1
Next j
End If
Next i
Next h
End Sub

示例输入 1:

Input

运行上面的代码后,输出为

Output after running macro

问题:现在,当我在第 3 行添加第二个条目并运行代码时,出现了问题:

输入:

enter image description here

代码生成的错误输出:

enter image description here

正确的输出应该是:

enter image description here

我无法确定我的代码哪里出了问题。请帮忙。

编辑:样本2:输入:

enter image description here

输出:

enter image description here

最佳答案

我编辑了您的代码并添加了注释。

更新的代码:

Sub mycode()
Application.ScreenUpdating = False 'Optional speedup code
Dim lastrow1 As Long
lastrow1 = Range("B" & Rows.Count).End(xlUp).Row
Dim Inputs() As Variant 'Create an array to hold positions
ReDim Inputs(lastrow1 - 1) 'Make it big enough to hold all positions
For x = 2 To lastrow1 'For each Position
Inputs(x - 1) = Cells(x, 4) 'Store The Position
Next x
OutRow = 2 'Row to output to
Increment = 10 'Increment
For Each c In Range("B2:B" & lastrow1) 'For each "count"
For j = 0 To c.Value
Cells(OutRow, 3).Value = c.Offset(0, -1).Value 'Put the letter in column C
If j = 0 Then 'If it's the first new letter, start at the position
Cells(OutRow, 4).Value = Inputs(c.Row - 1)
Else 'Otherwise, just add our increment to the number above
Cells(OutRow, 4).Value = Cells(OutRow - 1, 4).Value + Increment
End If
OutRow = OutRow + 1
Next j
Next c
Application.ScreenUpdating = True 'Optional speedup code
End Sub

最终输出:

Pic4

关于excel - 如何使用另一列中的值的引用来增加一列中的值,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/37625763/

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