javascript - Promise.then() 返回 Promise { }

Question

这个问题已经有答案了:

How do I return the response from an asynchronous call? (42 个回答)

已关闭 2 年前。

函数 fetchData 返回一个 promise ，然后我通过链接 promise 在generateURL函数中处理该 promise 。与 .then但是它返回 Promise 。函数generateURL应该返回一个字符串我做错了什么？

const fetch = require('node-fetch');

const fetchData = async () => {
  return await fetch('https://jsonplaceholder.typicode.com/todos/1');
};

const generateURL = () => {
  const baseURL = 'https://cdn.test.com/';
  fetchData().then((res) => {
    const data = res.json();
    console.log('data', data);
    const id = data.id;
    console.log('id', id);
    const generatedURL = `${baseURL}${id}`;
    return generatedURL;
  });
};
 

Answer 1

减少了一点代码，而不是添加多个 promise 解析

  const fetch = require('node-fetch');

const everything = async () =>{
    const response = await fetch('https://jsonplaceholder.typicode.com/todos/1');
    const {id} = await response.json();
    return `https://cdn.test.com/${id}`
}
everything().then((res)=>console.log(res));