docker - 在执行Docker运行时传递参数

Question

如果我有以下Dockfile

FROM centos:8
RUN yum update -y
RUN yum install -y python38-pip
COPY . /app
WORKDIR /app
RUN pip3 install -r requirements.txt
ENTRYPOINT ["python3"]
CMD ["app.py"]

随着应用程序如下:

#!/usr/bin/python
import sys
print('Here is your param: ', sys.argv[0])

当我调用docker run -it(myimg)时，如何传递参数，使输出成为参数？
例如:

docker run -it (myparam) "testfoo"

would print 

Here is your param: testfoo

Answer 1

sys.argv[0]指的是FileName，因此在运行testfoo时不会指望docker run -it my_image testfoo

The first item in the list, sys.argv[0], is the name of the Python script. The rest of the list elements, sys.argv[1] to sys.argv[n], are the command line arguments 2 through n

print('Here is your param: file Name', sys.argv[0],'args testfoo:',sys.argv[1])

因此，您可以将入口点替换为下面的内容，然后很好地传递运行时参数 testfoo

ENTRYPOINT ["python3","app.py"]

现在传递参数 testfoo

docker run -it --rm my_image testfoo