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javascript - validateLogin 是一个未定义的函数。(javascript 异常)

转载 作者:行者123 更新时间:2023-12-02 18:47:30 26 4
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嗨,我收到错误,因为未定义函数,我认为我的代码是好吧,在这种情况下有人可以帮忙吗?请帮助并建议我通过 ajax 方法通过 Web 服务获取数据的好教程。

<script type="text/javascript" language="javascript" src="Scripts/jquery-1.4.1.js">

function validatelogin() {

$('input[type=button]').attr('disabled', true);
$("#login").html('');
var loginId = $('#txt_id').attr('value'); // get username
var password = $('#txt_pwd').attr('value'); // get password

$.ajax({

type: "POST",
url: "WebService.asmx/validateLogin",
data: "lognId=" + loginId + "&password=" + password,
contentType: "application/json; charset=utf-8",

success: function (result) {
returnVal = result.d;
alert(returnVal);
},

error: function (XMLHttpRequest, textStatus, errorThrown) {
returnVal = '';
},
});
}


</script>

最佳答案

您无法链接 JavaScript 源文件并在同一标记中定义代码。只需将它们分成两个单独的标签,如下所示:

<script type="text/javascript" src="Scripts/jquery-1.4.1.js"></script>
<script type="text/javascript">
function validatelogin() {

$('input[type=button]').attr('disabled', true);
$("#login").html('');
var loginId = $('#txt_id').attr('value'); // get username
var password = $('#txt_pwd').attr('value'); // get password

$.ajax({

type: "POST",
url: "WebService.asmx/validateLogin",
data: "lognId=" + loginId + "&password=" + password,
contentType: "application/json; charset=utf-8",

success: function (result) {
returnVal = result.d;
alert(returnVal);
},

error: function (XMLHttpRequest, textStatus, errorThrown) {
returnVal = '';
},
});
}


</script>

引用MDN on the issue :

src

This attribute specifies the URI of an external script; this can be used as an alternative to embedding a script directly within a document. script elements with an src attribute specified should not have a script embedded within its tags.

关于javascript - validateLogin 是一个未定义的函数。(javascript 异常),我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/16211629/

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