javascript - 如何在JS中删除存储在数组中的输入

Question

let input;
const todos = [];

while (input !== 'exit') {
    input = prompt('Type what you want to do');
    if (input === 'new') {
        input = prompt("What's your todo?");
        todos.push(input);
    } else if (input === 'list') {
        console.log(`This is your list of todos: ${todos}`);
    } else if (input === 'delete') {
        input = prompt('Which todo would you like to delete?');
        if (todos.indexOf(input) !== -1) {
            todos.splice(1, 1, input);
            console.log(`You've deleted ${input}`);
        }
    } else {
        break;
    }
}

这就是我到目前为止所尝试过的。我正在开始编程，这是一个小练习的一部分，我必须根据提示要求添加新的待办事项，列出所有内容，然后删除。我想做的是:获取存储在输入变量中的输入，然后检查它是否在数组内部，如果它是肯定的，我想删除它，而不是从索引中删除它，而是从单词中删除。

喜欢:

-删除-吃//检查其是否在数组内部//如果为 true 则将其删除

如果这是一个愚蠢的问题，我深表歉意。我在网上试了一下，没找到。

谢谢!

Answer 1

您可以将循环更改为 do while 循环来检查退出，而不是在最后检查时使用 break 。

然后需要存储indexOf的结果，并将item与index拼接起来。

let input;
const todos = [];

do {
  input = prompt('Type what you want to do');
  if (input === 'new') {
    input = prompt("What's your todo?");
    todos.push(input);
  } else if (input === 'list') {
    console.log(`This is your list of todos: ${todos}`);
  } else if (input === 'delete') {
    input = prompt('Which todo would you like to delete?');
    const index = todos.indexOf(input)
    if (index !== -1) {
      todos.splice(index, 1);
      console.log(`You've deleted ${input}`);
    }
  }
} while (input !== 'exit');

更好的方法是采用 switch statement .

let input;
const todos = [];

do {
    input = prompt('Type what you want to do');
    switch (input) {
        case 'new':
            input = prompt("What's your todo?");
            todos.push(input);
            break;
        case 'list':
            console.log(`This is your list of todos: ${todos}`);
            break;
        case 'delete':
            input = prompt('Which todo would you like to delete?');
            const index = todos.indexOf(input)
            if (index !== -1) {
                todos.splice(index, 1);
                console.log(`You've deleted ${input}`);
            }
    }
} while (input !== 'exit');