- html - 出于某种原因,IE8 对我的 Sass 文件中继承的 html5 CSS 不友好?
- JMeter 在响应断言中使用 span 标签的问题
- html - 在 :hover and :active? 上具有不同效果的 CSS 动画
- html - 相对于居中的 html 内容固定的 CSS 重复背景?
这是我的数据示例以及我希望看到的内容:
JOB OPSEQ OPCOMPLETE OPCODE
100 1 yes pull
100 2 yes weld
100 3 no grind
100 4 no machine
100 5 no asmbl
所以我想选择 opcomplete=no 的 min(opseq) 和 opcomplete=yes 的 max(opseq),以及 min 和 max opseq 的操作码。在此示例中,将是:
分钟(opseq):3
最小操作的操作码:grind
最大值(opseq):2最大操作的操作码:焊接
我寻找这个的原因是为了获取不完整的最小opseq的操作码。
我让最小和最大 opseq 工作得很好。这就是我所拥有的:
(SELECT company, jobnum, MAX(oprseq) AS maxclosed, opcomplete
FROM joboper AS joboper_2
WHERE (company = 'lot') AND (opcomplete = '1')
GROUP BY company, jobnum, opcomplete) AS t_joboper1 ON joboper.company = t_joboper1.company AND joboper.jobnum = t_joboper1.jobnum INNER JOIN
(SELECT company, jobnum, MIN(oprseq) AS minopen, opcomplete
FROM joboper AS joboper_1
WHERE (company = 'lot') AND (opcomplete = '0')
GROUP BY company, jobnum, opcomplete) AS t_joboper2 ON joboper.company = t_joboper2.company AND joboper.jobnum = t_joboper2.jobnum
因此,当我尝试添加操作码时,它不起作用,并且我开始收到各种重复值。这是我写的:
(SELECT company, jobnum, MAX(oprseq) AS maxclosed, opcomplete, opcode as maxopcode
FROM joboper AS joboper_2
WHERE (company = 'lot') AND (opcomplete = '1')
GROUP BY company, jobnum, opcomplete, opcode) AS t_joboper1 ON joboper.company = t_joboper1.company AND joboper.jobnum = t_joboper1.jobnum INNER JOIN
(SELECT company, jobnum, MIN(oprseq) AS minopen, opcomplete, opcode as minopcode
FROM joboper AS joboper_1
WHERE (company = 'lot') AND (opcomplete = '0')
GROUP BY company, jobnum, opcomplete, opcode) AS t_joboper2 ON joboper.company = t_joboper2.company AND joboper.jobnum = t_joboper2.jobnum
这是我目前的完整代码(操作码拉入所有重复值:
SELECT jobhead.company, jobhead.jobnum, jobhead.partnum,
jobhead.partdescription, jobhead.startdate,
jobhead.reqduedate, jobhead.prodqty, jobhead.qtycompleted,
joboper.oprseq, joboper.opcode, joboper.opcomplete,
joboper.qtycompleted AS joboperqtycomplete,
resourcegroup.description AS rgroupdescription,
dmrhead.dmrnum, poheader.ponum, vendor.name AS vendorname,
t_joboper2.minopen AS minopen, t_joboper2.minopcode AS minopcode,
t_joboper1.maxclosed AS maxclosed, t_joboper1.maxopcode AS maxopcode
FROM jobhead LEFT OUTER JOIN
joboper INNER JOIN
(SELECT company, jobnum, MAX(oprseq) AS maxclosed,
opcomplete, opcode as maxopcode
FROM joboper AS joboper_2
WHERE (company = 'lot') AND (opcomplete = '1')
GROUP BY company, jobnum, opcomplete, opcode) AS t_joboper1
ON joboper.company = t_joboper1.company
AND joboper.jobnum = t_joboper1.jobnum INNER JOIN
(SELECT company, jobnum, MIN(oprseq) AS minopen, opcomplete,
opcode as minopcode
FROM joboper AS joboper_1
WHERE (company = 'lot') AND (opcomplete = '0')
GROUP BY company, jobnum, opcomplete, opcode) AS t_joboper2
ON joboper.company = t_joboper2.company
AND joboper.jobnum = t_joboper2.jobnum
ON jobhead.company = joboper.company
AND jobhead.jobnum = joboper.jobnum LEFT OUTER JOIN
resourcegroup ON joboper.company = resourcegroup.company
AND joboper.opcode = resourcegroup.opcode LEFT OUTER JOIN
dmrhead ON joboper.company = dmrhead.company
AND joboper.jobnum = dmrhead.jobnum
AND joboper.assemblyseq = dmrhead.assemblyseq
AND joboper.oprseq = dmrhead.oprseq LEFT OUTER JOIN
porel ON joboper.company = porel.company
AND joboper.jobnum = porel.jobnum
AND joboper.assemblyseq = porel.assemblyseq
AND joboper.oprseq = porel.jobseq LEFT OUTER JOIN
podetail ON porel.company = podetail.company
AND porel.ponum = podetail.ponum
AND porel.poline = podetail.poline LEFT OUTER JOIN
poheader ON podetail.company = poheader.company
AND podetail.ponum = poheader.ponum LEFT OUTER JOIN
vendor ON poheader.company = vendor.company
AND poheader.vendornum = vendor.vendornum
WHERE (jobhead.jobreleased = 1)
AND (jobhead.jobcomplete = 0)
AND (jobhead.company = 'lot')
AND (jobhead.plant = '001')
我希望这一切都有意义我在这里尝试做的事情。如果不是很明显,这是我第一次在这里问问题。预先感谢所有的帮助!!!
新 - 2012 年 12 月 21 日
谢谢两位的帮助!我尝试了您的两种建议,但都无法获得我想要的确切结果。但每个答案都帮助我了解了最终需要什么才能得到我所需要的东西。由于这是我的第一个问题,我不知道应该做什么来将哪个答案标记为解决方案?就像我说的,这两个答案都对我有很大帮助,我认为我无法从中得到我想要的结果的原因完全是我的错。经过更多研究后,我意识到,尽管我非常努力地想弄清楚我的问题,但当我回去时,我发现我可以如何更好地措辞。再次,我非常感谢所有的帮助,并期待将来提出更好的问题!
顺便说一下,这是最终有效的代码。
SELECT jobhead.company, jobhead.jobnum, jobhead.partnum, jobhead.partdescription, jobhead.startdate, jobhead.reqduedate, jobhead.prodqty, jobhead.qtycompleted,
joboper.oprseq, joboper.opcode, joboper.opcomplete, joboper.qtycompleted AS joboperqtycomplete, resourcegroup.description AS rgroupdescription,
dmrhead.dmrnum, poheader.ponum, vendor.name AS vendorname, t_joboper2.minopen, t_joboper1.maxclosed, t_joboper3.opcode AS minopcode
FROM jobhead LEFT OUTER JOIN
joboper INNER JOIN
(SELECT company, jobnum, MAX(oprseq) AS maxclosed, opcomplete
FROM joboper AS joboper_1
WHERE (company = 'lot') AND (opcomplete = '1')
GROUP BY company, jobnum, opcomplete) AS t_joboper1 ON joboper.company = t_joboper1.company AND joboper.jobnum = t_joboper1.jobnum INNER JOIN
(SELECT company, jobnum, MIN(oprseq) AS minopen, opcomplete
FROM joboper AS joboper_2
WHERE (company = 'lot') AND (opcomplete = '0')
GROUP BY company, jobnum, opcomplete) AS t_joboper2 ON joboper.company = t_joboper2.company AND
joboper.jobnum = t_joboper2.jobnum INNER JOIN
(SELECT company, jobnum, oprseq, opcomplete, opcode
FROM joboper AS joboper_3
WHERE (company = 'lot') AND (opcomplete = '0'))
AS t_joboper3 ON t_joboper2.company = t_joboper3.company AND t_joboper2.jobnum = t_joboper3.jobnum AND
t_joboper2.minopen = t_joboper3.oprseq ON jobhead.company = joboper.company AND jobhead.jobnum = joboper.jobnum LEFT OUTER JOIN
resourcegroup ON joboper.company = resourcegroup.company AND joboper.opcode = resourcegroup.opcode LEFT OUTER JOIN
dmrhead ON joboper.company = dmrhead.company AND joboper.jobnum = dmrhead.jobnum AND joboper.assemblyseq = dmrhead.assemblyseq AND
joboper.oprseq = dmrhead.oprseq LEFT OUTER JOIN
porel ON joboper.company = porel.company AND joboper.jobnum = porel.jobnum AND joboper.assemblyseq = porel.assemblyseq AND
joboper.oprseq = porel.jobseq LEFT OUTER JOIN
podetail ON porel.company = podetail.company AND porel.ponum = podetail.ponum AND porel.poline = podetail.poline LEFT OUTER JOIN
poheader ON podetail.company = poheader.company AND podetail.ponum = poheader.ponum LEFT OUTER JOIN
vendor ON poheader.company = vendor.company AND poheader.vendornum = vendor.vendornum
WHERE (jobhead.jobreleased = 1) AND (jobhead.jobcomplete = 0) AND (jobhead.company = 'lot') AND (jobhead.plant = '001')
最佳答案
这是一种方法:
select JOB,
min(case when OPCOMPLETE = 'no' then OPSEQ end) as MIN_NO_OPSEQ,
min(case when OPCOMPLETE = 'no' then OPCODE end) as MIN_NO_OPCODE,
min(case when OPCOMPLETE = 'yes' then OPSEQ end) as MAX_YES_OPSEQ,
min(case when OPCOMPLETE = 'yes' then OPCODE end) as MAX_YES_OPCODE
from ( select JOB,
OPSEQ,
OPCOMPLETE,
OPCODE,
rank() over (partition by JOB, OPCOMPLETE order by OPSEQ asc) as R_NO,
rank() over (partition by JOB, OPCOMPLETE order by OPSEQ desc) as R_YES
from TABLE_NAME
)
where OPCOMPLETE = 'no' and R_NO = 1 -- row with min(OPSEQ) where OPCOMPLETE = 'no'
or OPCOMPLETE = 'yes' and R_YES = 1 -- row with max(OPSEQ) where OPCOMPLETE = 'yes'
group
by JOB
;
注释:
min
都可以更改为 max
,但没有任何效果,因为只有一行能够满足所有必要的条件。 min
(或 max
)只是因为 group by
才需要:我们通过选择非空行将两行合并为一行值。rank()
的信息,请参阅 its documentation on MSDN .关于sql-server - 获取具有 MIN/MAX 值的行的其他字段值,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/13979553/
我需要您在以下方面提供帮助。近一个月来,我一直在阅读有关任务和异步的内容。 我想尝试在一个简单的 wep api 项目中实现我新获得的知识。我有以下方法,并且它们都按预期工作: public Htt
我的可执行 jar 中有一个模板文件 (.xls)。不需要在运行时我需要为这个文件创建 100 多个副本(稍后将唯一地附加)。用于获取 jar 文件中的资源 (template.xls)。我正在使用
我在查看网站的模型代码时对原型(prototype)有疑问。我知道这对 Javascript 中的继承很有用。 在这个例子中... define([], function () { "use
影响我性能的前三项操作是: 获取滚动条 获取偏移高度 Ext.getStyle 为了解释我的应用程序中发生了什么:我有一个网格,其中有一列在每个单元格中呈现网格。当我几乎对网格的内容做任何事情时,它运
我正在使用以下函数来获取 URL 参数。 function gup(name, url) { name = name.replace(/[\[]/, '\\\[').replace(/[\]]/,
我最近一直在使用 sysctl 来做很多事情,现在我使用 HW_MACHINE_ARCH 变量。我正在使用以下代码。请注意,当我尝试获取其他变量 HW_MACHINE 时,此代码可以完美运行。我还认为
关闭。这个问题不符合Stack Overflow guidelines .它目前不接受答案。 关闭 9 年前。 要求提供代码的问题必须表现出对所解决问题的最低限度的理解。包括尝试过的解决方案、为什么
由于使用 main-bower-files 作为使用 Gulp 的编译任务的一部分,我无法使用 node_modules 中的 webpack 来require 模块code> dir 因为我会弄乱当
关闭。这个问题需要更多focused .它目前不接受答案。 想改进这个问题吗? 更新问题,使其只关注一个问题 editing this post . 关闭 5 年前。 Improve this qu
我使用 Gridlayout 在一行中放置 4 个元素。首先,我有一个 JPanel,一切正常。对于行数变大并且我必须能够向下滚动的情况,我对其进行了一些更改。现在我的 JPanel 上添加了一个 J
由于以下原因,我想将 VolumeId 的值保存在变量中: #!/usr/bin/env python import boto3 import json import argparse import
我正在将 MSAL 版本 1.x 更新为 MSAL-browser 的 Angular 。所以我正在尝试从版本 1.x 迁移到 2.X.I 能够成功替换代码并且工作正常。但是我遇到了 acquireT
我知道有很多关于此的问题,例如 Getting daily averages with pandas和 How get monthly mean in pandas using groupby但我遇到
This is the query string that I am receiving in URL. Output url: /demo/analysis/test?startDate=Sat+
我正在尝试使用 javascript 中的以下代码访问 Geoserver 层 var gkvrtWmsSource =new ol.source.ImageWMS({ u
API 需要一个包含授权代码的 header 。这就是我到目前为止所拥有的: var fullUrl = 'https://api.ecobee.com/1/thermostat?json=\{"s
如何获取文件中的最后一个字符,如果是某个字符,则删除它而不将整个文件加载到内存中? 这就是我目前所拥有的。 using (var fileStream = new FileStream("file.t
我是这个社区的新手,想出了我的第一个问题。 我正在使用 JSP,我成功地创建了 JSP-Sites,它正在使用jsp:setParameter 和 jsp:getParameter 具有单个字符串。
在回答 StoreStore reordering happens when compiling C++ for x86 @Peter Cordes 写过 For Acquire/Release se
我有一个函数,我们将其命名为 X1,它返回变量 Y。该函数在操作 .on("focusout", X1) 中使用。如何获取变量Y?执行.on后X1的结果? 最佳答案 您可以更改 Y 的范围以使其位于函
我是一名优秀的程序员,十分优秀!