gpt4 book ai didi

sql-server - 获取具有 MIN/MAX 值的行的其他字段值

转载 作者:行者123 更新时间:2023-12-02 18:40:33 25 4
gpt4 key购买 nike

这是我的数据示例以及我希望看到的内容:

JOB    OPSEQ    OPCOMPLETE   OPCODE

100 1 yes pull
100 2 yes weld
100 3 no grind
100 4 no machine
100 5 no asmbl

所以我想选择 opcomplete=no 的 min(opseq) 和 opcomplete=yes 的 max(opseq),以及 min 和 max opseq 的操作码。在此示例中,将是:
分钟(opseq):3
最小操作的操作码:grind
最大值(opseq):2最大操作的操作码:焊接

我寻找这个的原因是为了获取不完整的最小opseq的操作码。
我让最小和最大 opseq 工作得很好。这就是我所拥有的:

(SELECT   company, jobnum, MAX(oprseq) AS maxclosed, opcomplete
FROM joboper AS joboper_2
WHERE (company = 'lot') AND (opcomplete = '1')
GROUP BY company, jobnum, opcomplete) AS t_joboper1 ON joboper.company = t_joboper1.company AND joboper.jobnum = t_joboper1.jobnum INNER JOIN
(SELECT company, jobnum, MIN(oprseq) AS minopen, opcomplete
FROM joboper AS joboper_1
WHERE (company = 'lot') AND (opcomplete = '0')
GROUP BY company, jobnum, opcomplete) AS t_joboper2 ON joboper.company = t_joboper2.company AND joboper.jobnum = t_joboper2.jobnum

因此,当我尝试添加操作码时,它不起作用,并且我开始收到各种重复值。这是我写的:

(SELECT   company, jobnum, MAX(oprseq) AS maxclosed, opcomplete, opcode as maxopcode
FROM joboper AS joboper_2
WHERE (company = 'lot') AND (opcomplete = '1')
GROUP BY company, jobnum, opcomplete, opcode) AS t_joboper1 ON joboper.company = t_joboper1.company AND joboper.jobnum = t_joboper1.jobnum INNER JOIN
(SELECT company, jobnum, MIN(oprseq) AS minopen, opcomplete, opcode as minopcode
FROM joboper AS joboper_1
WHERE (company = 'lot') AND (opcomplete = '0')
GROUP BY company, jobnum, opcomplete, opcode) AS t_joboper2 ON joboper.company = t_joboper2.company AND joboper.jobnum = t_joboper2.jobnum

这是我目前的完整代码(操作码拉入所有重复值:

SELECT     jobhead.company, jobhead.jobnum, jobhead.partnum, 
jobhead.partdescription, jobhead.startdate,
jobhead.reqduedate, jobhead.prodqty, jobhead.qtycompleted,
joboper.oprseq, joboper.opcode, joboper.opcomplete,
joboper.qtycompleted AS joboperqtycomplete,
resourcegroup.description AS rgroupdescription,
dmrhead.dmrnum, poheader.ponum, vendor.name AS vendorname,
t_joboper2.minopen AS minopen, t_joboper2.minopcode AS minopcode,
t_joboper1.maxclosed AS maxclosed, t_joboper1.maxopcode AS maxopcode
FROM jobhead LEFT OUTER JOIN
joboper INNER JOIN
(SELECT company, jobnum, MAX(oprseq) AS maxclosed,
opcomplete, opcode as maxopcode
FROM joboper AS joboper_2
WHERE (company = 'lot') AND (opcomplete = '1')
GROUP BY company, jobnum, opcomplete, opcode) AS t_joboper1
ON joboper.company = t_joboper1.company
AND joboper.jobnum = t_joboper1.jobnum INNER JOIN
(SELECT company, jobnum, MIN(oprseq) AS minopen, opcomplete,
opcode as minopcode
FROM joboper AS joboper_1
WHERE (company = 'lot') AND (opcomplete = '0')
GROUP BY company, jobnum, opcomplete, opcode) AS t_joboper2
ON joboper.company = t_joboper2.company
AND joboper.jobnum = t_joboper2.jobnum
ON jobhead.company = joboper.company
AND jobhead.jobnum = joboper.jobnum LEFT OUTER JOIN
resourcegroup ON joboper.company = resourcegroup.company
AND joboper.opcode = resourcegroup.opcode LEFT OUTER JOIN
dmrhead ON joboper.company = dmrhead.company
AND joboper.jobnum = dmrhead.jobnum
AND joboper.assemblyseq = dmrhead.assemblyseq
AND joboper.oprseq = dmrhead.oprseq LEFT OUTER JOIN
porel ON joboper.company = porel.company
AND joboper.jobnum = porel.jobnum
AND joboper.assemblyseq = porel.assemblyseq
AND joboper.oprseq = porel.jobseq LEFT OUTER JOIN
podetail ON porel.company = podetail.company
AND porel.ponum = podetail.ponum
AND porel.poline = podetail.poline LEFT OUTER JOIN
poheader ON podetail.company = poheader.company
AND podetail.ponum = poheader.ponum LEFT OUTER JOIN
vendor ON poheader.company = vendor.company
AND poheader.vendornum = vendor.vendornum
WHERE (jobhead.jobreleased = 1)
AND (jobhead.jobcomplete = 0)
AND (jobhead.company = 'lot')
AND (jobhead.plant = '001')

我希望这一切都有意义我在这里尝试做的事情。如果不是很明显,这是我第一次在这里问问题。预先感谢所有的帮助!!!

新 - 2012 年 12 月 21 日

谢谢两位的帮助!我尝试了您的两种建议,但都无法获得我想要的确切结果。但每个答案都帮助我了解了最终需要什么才能得到我所需要的东西。由于这是我的第一个问题,我不知道应该做什么来将哪个答案标记为解决方案?就像我说的,这两个答案都对我有很大帮助,我认为我无法从中得到我想要的结果的原因完全是我的错。经过更多研究后,我意识到,尽管我非常努力地想弄清楚我的问题,但当我回去时,我发现我可以如何更好地措辞。再次,我非常感谢所有的帮助,并期待将来提出更好的问题!
顺便说一下,这是最终有效的代码。

 SELECT     jobhead.company, jobhead.jobnum, jobhead.partnum, jobhead.partdescription, jobhead.startdate, jobhead.reqduedate, jobhead.prodqty, jobhead.qtycompleted, 
joboper.oprseq, joboper.opcode, joboper.opcomplete, joboper.qtycompleted AS joboperqtycomplete, resourcegroup.description AS rgroupdescription,
dmrhead.dmrnum, poheader.ponum, vendor.name AS vendorname, t_joboper2.minopen, t_joboper1.maxclosed, t_joboper3.opcode AS minopcode
FROM jobhead LEFT OUTER JOIN
joboper INNER JOIN
(SELECT company, jobnum, MAX(oprseq) AS maxclosed, opcomplete
FROM joboper AS joboper_1
WHERE (company = 'lot') AND (opcomplete = '1')
GROUP BY company, jobnum, opcomplete) AS t_joboper1 ON joboper.company = t_joboper1.company AND joboper.jobnum = t_joboper1.jobnum INNER JOIN
(SELECT company, jobnum, MIN(oprseq) AS minopen, opcomplete
FROM joboper AS joboper_2
WHERE (company = 'lot') AND (opcomplete = '0')
GROUP BY company, jobnum, opcomplete) AS t_joboper2 ON joboper.company = t_joboper2.company AND
joboper.jobnum = t_joboper2.jobnum INNER JOIN
(SELECT company, jobnum, oprseq, opcomplete, opcode
FROM joboper AS joboper_3
WHERE (company = 'lot') AND (opcomplete = '0'))
AS t_joboper3 ON t_joboper2.company = t_joboper3.company AND t_joboper2.jobnum = t_joboper3.jobnum AND
t_joboper2.minopen = t_joboper3.oprseq ON jobhead.company = joboper.company AND jobhead.jobnum = joboper.jobnum LEFT OUTER JOIN
resourcegroup ON joboper.company = resourcegroup.company AND joboper.opcode = resourcegroup.opcode LEFT OUTER JOIN
dmrhead ON joboper.company = dmrhead.company AND joboper.jobnum = dmrhead.jobnum AND joboper.assemblyseq = dmrhead.assemblyseq AND
joboper.oprseq = dmrhead.oprseq LEFT OUTER JOIN
porel ON joboper.company = porel.company AND joboper.jobnum = porel.jobnum AND joboper.assemblyseq = porel.assemblyseq AND
joboper.oprseq = porel.jobseq LEFT OUTER JOIN
podetail ON porel.company = podetail.company AND porel.ponum = podetail.ponum AND porel.poline = podetail.poline LEFT OUTER JOIN
poheader ON podetail.company = poheader.company AND podetail.ponum = poheader.ponum LEFT OUTER JOIN
vendor ON poheader.company = vendor.company AND poheader.vendornum = vendor.vendornum
WHERE (jobhead.jobreleased = 1) AND (jobhead.jobcomplete = 0) AND (jobhead.company = 'lot') AND (jobhead.plant = '001')

最佳答案

这是一种方法:

select JOB,
min(case when OPCOMPLETE = 'no' then OPSEQ end) as MIN_NO_OPSEQ,
min(case when OPCOMPLETE = 'no' then OPCODE end) as MIN_NO_OPCODE,
min(case when OPCOMPLETE = 'yes' then OPSEQ end) as MAX_YES_OPSEQ,
min(case when OPCOMPLETE = 'yes' then OPCODE end) as MAX_YES_OPCODE
from ( select JOB,
OPSEQ,
OPCOMPLETE,
OPCODE,
rank() over (partition by JOB, OPCOMPLETE order by OPSEQ asc) as R_NO,
rank() over (partition by JOB, OPCOMPLETE order by OPSEQ desc) as R_YES
from TABLE_NAME
)
where OPCOMPLETE = 'no' and R_NO = 1 -- row with min(OPSEQ) where OPCOMPLETE = 'no'
or OPCOMPLETE = 'yes' and R_YES = 1 -- row with max(OPSEQ) where OPCOMPLETE = 'yes'
group
by JOB
;

注释:

  • 未经测试。
  • 在第 2-5 行中,每个 min 都可以更改为 max,但没有任何效果,因为只有一行能够满足所有必要的条件。 min(或 max)只是因为 group by 才需要:我们通过选择非空行将两行合并为一行值。
  • 有关 rank() 的信息,请参阅 its documentation on MSDN .

关于sql-server - 获取具有 MIN/MAX 值的行的其他字段值,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/13979553/

25 4 0
Copyright 2021 - 2024 cfsdn All Rights Reserved 蜀ICP备2022000587号
广告合作:1813099741@qq.com 6ren.com