php - 使用 xmlhttp.responseText 中的 JSON 解析数组

Question

我尝试使用ajax将php数组获取到js，并在PHP中通过JSON编码并在JS中解码，但无法获得所需的结果。

我在回显编码字符串之前使用 var_dump，这是输出:

$boardArrayEncoded = json_encode($boardArray);
var_dump($boardArrayEncoded);
echo $boardArrayEncoded;

JSON_encode 后的字符串是:

string '{"1x1":0,"1x2":0,"1x3":0,"1x4":0,"1x5":0,"1x6":0,"2x1":0,"2x2":0,"2x3":0,"2x4":0,"2x5":0,"2x6":0,"3x1":0,"3x2":0,"3x3":0,"3x4":0,"3x5":0,"3x6":0,"4x1":0,"4x2":0,"4x3":0,"4x4":0,"4x5":0,"4x6":0,"5x1":0,"5x2":0,"5x3":0,"5x4":0,"5x5":0,"5x6":0,"6x1":0,"6x2":0,"6x3":0,"6x4":0,"6x5":0,"6x6":0}'

在 javascript 中我尝试解析它:

if (xmlhttp.readyState == 4 && xmlhttp.status == 200)
{
   document.getElementById("logDiv1").innerHTML = xmlhttp.responseText;
   array = JSON.parse(xmlhttp.responseText);
}

这是 xmlhttp.responseText:{"1x1":0,"1x2":0,"1x3":0,"1x4":0,"1x5":0,"1x6":0, "2x1":0,"2x2":0,"2x3":0,"2x4":0,"2x5":0,"2x6":0,"3x1":0,"3x2":0,"3x3 ":0,"3x4":0,"3x5":0,"3x6":0,"4x1":0,"4x2":0,"4x3":0,"4x4":0,"4x5": 0,"4x6":0,"5x1":0,"5x2":0,"5x3":0,"5x4":0,"5x5":0,"5x6":0,"6x1":0, "6x2":0,"6x3":0,"6x4":0,"6x5":0,"6x6":0}

在 Firebug 上我收到语法错误:

SyntaxError: JSON.parse: unexpected character
[Break On This Error]   

array1 = JSON.parse(xmlhttp.responseText);

我做错了什么？我需要在 JS 中使用这个数组，如何正确编码？

提前致谢

Answer 1

删除 var_dump。它是打印输出，这可能导致您所说的responseText不是完整的responseText。

我希望您的回复文本是:

string '{"1x1":0,"1x2":0,"1x3":0,"1x4":0,"1x5":0,"1x6":0,"2x1":0,"2x2":0,"2x3":0,"2x4":0,"2x5":0,"2x6":0,"3x1":0,"3x2":0,"3x3":0,"3x4":0,"3x5":0,"3x6":0,"4x1":0,"4x2":0,"4x3":0,"4x4":0,"4x5":0,"4x6":0,"5x1":0,"5x2":0,"5x3":0,"5x4":0,"5x5":0,"5x6":0,"6x1":0,"6x2":0,"6x3":0,"6x4":0,"6x5":0,"6x6":0}'
{"1x1":0,"1x2":0,"1x3":0,"1x4":0,"1x5":0,"1x6":0,"2x1":0,"2x2":0,"2x3":0,"2x4":0,"2x5":0,"2x6":0,"3x1":0,"3x2":0,"3x3":0,"3x4":0,"3x5":0,"3x6":0,"4x1":0,"4x2":0,"4x3":0,"4x4":0,"4x5":0,"4x6":0,"5x1":0,"5x2":0,"5x3":0,"5x4":0,"5x5":0,"5x6":0,"6x1":0,"6x2":0,"6x3":0,"6x4":0,"6x5":0,"6x6":0}