javascript - 从父对象创建具有相同属性值的子对象

Question

这个问题已经有答案了:

How to put items into grouped arrays where grouped by a particular key (3 个回答)

已关闭 9 年前。

我有一个父对象。我想使用相同的键值对从父对象创建子对象。

例如

parentJSON = {[name:"a1",address:"b1",comp:"c1"],
              [name:"a2",address:"b2",comp:"c1"],
              [name:"a3",address:"b3",comp:"c2"],
              [name:"a4",address:"b4",comp:"c2"],
              [name:"a5",address:"b5",comp:"c2"],
              [name:"a6",address:"b6",comp:"c3"]}

现在我想创建具有相同“comp”值的子对象。

例如

childJSON1 = {[name:"a1",address:"b1",comp:"c1"],
              [name:"a2",address:"b2",comp:"c1"]}

childJSON2 = {[name:"a3",address:"b3",comp:"c2"],
              [name:"a4",address:"b4",comp:"c2"],
              [name:"a5",address:"b5",comp:"c2"]}

childJSON3 = {[name:"a6",address:"b6",comp:"c3"]}

这就是我尝试做的一点(它将使用指示重复次数的键更改父对象):

parentJSON = [1,2,3,3,4,4,4,5];
var i=0, x, count, item;

while(i < parentJSON.length) {
    count = 1;
    item = parentJSON[i];
    x = i+1;

    while(x < parentJSON.length && 
            (x = parentJSON.indexOf(item, x)) != -1) {

        count += 1;
        parentJSON.splice(x,1);
    }

    parentJSON[i] = new Array(parentJSON[i],count);
    ++i;
}

console.log(parentJSON);`

Answer 1

首先你的json格式不正确，它应该看起来像这样

                   [{name:"a1",address:"b1",comp:"c1"},
                   {name:"a2",address:"b2",comp:"c1"},
                   {name:"a3",address:"b3",comp:"c2"},
                   {name:"a4",address:"b4",comp:"c2"},
                   {name:"a5",address:"b5",comp:"c2"},
                   {name:"a6",address:"b6",comp:"c3"}]

对象数组。

我的尝试，也非常可读。

var result = {};

$.each(parentJSON, function (i, item) {
    if(!result[item.comp]) {
        result[item.comp] = [];
    }

    (result[item.comp]).push(item);
});

alert(JSON.stringify(result))

JsFiddle