python - 在Python中反转数字列表的数字

Question

for i in range(len(primo)):
    reversed_num = 0
    while i > 0:
       digit = i % 10
       reversed_num = reversed_num * 10 + digit
       i //= 10
       reversed.append (reversed_num)
    
for r in range(len(reversed)):
    print (r)

我正在编写一个程序来反转列表中的一系列数字。例如:

输入:1234,124,654

输出:4321,421,456

该脚本对于一个数字可以正常工作，但对于一个列表则无法正常工作。

编辑:......................................

这是完整的工作代码。

#program to find the multiple of the first number that summed to its reverse creates a number divisible for the second number chosen. Results are shown up to five digits.

import sys

def main():
    x = 0
    y = 0
    k = 0
    z = 0
    print ("Hello! Let's compare some numbers!\nPress input to continue")
    input()
    print ("Insert the first number")
    x = input()
    print ("Insert the second number")
    y = input()
    print()
    
    primo = []
    secondo = []
    
    #list multiples
    
    while k < 99999:
        k = int(k) + int(x)
        print (k)
        primo.append (k)
        
    while z < 99999:
        z = int(z) + int(y)
        print(z)
        secondo.append (z)
        
    print("The numbers have been calculated! Press to proceed")

    input()
    
    print("LOADING...")

    #reverse all numbers of the first list
    
    def myReverser(n: float) -> float:
       return float(''.join(list(reversed(str(n)))))
    
    reversedList = [myReverser(i) for i in primo]
    reversedList = [int(i) for i in reversedList]
    
    #sum the multiple of the first number and its reversed and search common values in res and secondo
    
    res = [
    x
    for x, y in zip(primo, reversedList)
    if (x + y) in secondo
]

    print()
    print()

    if len(res) == 0:
        print ("No results found")
    else:
        print ("The numbers are: ", res)

    #ending

    print ()
    print ("Thank you for using my program!")
    print ()
    choice = input ("Would you try with another number? [Y/N] ").capitalize()

    if choice == "Y":
        main()
    if choice == "N":
        sys.exit()

main()

#no copyright intended. This code is open-source. Feel free to use it in other projects.

该脚本可以比较两个给定的数字，以找到第一个数字的倍数，将其倒数相加，创建一个可被所选的第二个数字整除的数字。结果最多显示五位数字。

Answer 1

不错的尝试，但是反转数字的函数怎么样？您应该很高兴知道 Python 中已经存在 reversed ，并且您可以这样使用它:

>>> list(reversed(str(0.1223142131)))
['1', '3', '1', '2', '4', '1', '3', '2', '2', '1', '.', '0']
>>> float(''.join(reversed(str(0.1223142131))))
1312413221.0

这样你就可以实现自己的功能:

def myReverser(n: float) -> float:
    return float(''.join(reversed(str(n))))

然后在整个列表上使用它:

reversedList = [myReverser(i) for i in [1234, 124, 654]]

---

如果您不希望所有数字末尾有.0，则意味着您不需要 float ，而是integers，所以你可以这样做:

reversedList = [int(i) for i in reversedList]