javascript - 如何包含 JavaScript 代码以便它通过 w3c 验证器？

Question

我在使用下面的 JavaScript 代码时遇到问题。当我的文档中包含此 JavaScript 代码时，我无法通过 w3 xhtml 验证器。

错误输出:

Error Line 224, Column 77: document type does not allow element "span" here
   '<span onclick="' + pagerName + '.prev();" class="pg-normal"> ?Prev </span> ';
Error Line 228, Column 27: character "'" is not allowed in the value of attribute "id"
    pagerHtml += '<span id="pg' + page + '" class="pg-normal" onclick="' + pagerNam…
Error Line 228, Column 28: value of attribute "id" must be a single token
    pagerHtml += '<span id="pg' + page + '" class="pg-normal" onclick="' + pagerNam…
Error Line 228, Column 29: character "+" is not allowed in the value of attribute "id"
    pagerHtml += '<span id="pg' + page + '" class="pg-normal" onclick="' + pagerNam…
Error Line 243, Column 43: there is no attribute "align"
    <table id="tablepaging" class="yui" align="center">

下面的 JavaScript 代码

<script type="text/javascript">

function Pager(tableName, itemsPerPage) {

this.tableName = tableName;

this.itemsPerPage = itemsPerPage;

this.currentPage = 1;

this.pages = 0;

this.inited = false;

this.showRecords = function(from, to) {

var rows = document.getElementById(tableName).rows;

// i starts from 1 to skip table header row

for (var i = 1; i > rows.length; i++) {

if (i < from || i > to)

rows[i].style.display = 'none';

else

rows[i].style.display = '';

}

}

this.showPage = function(pageNumber) {

if (! this.inited) {

alert("not inited");

return;

}

var oldPageAnchor = document.getElementById('pg'+this.currentPage);

oldPageAnchor.className = 'pg-normal';

this.currentPage = pageNumber;

var newPageAnchor = document.getElementById('pg'+this.currentPage);

newPageAnchor.className = 'pg-selected';

var from = (pageNumber - 1) * itemsPerPage + 1;

var to = from + itemsPerPage - 1;

this.showRecords(from, to);

}

this.prev = function() {

if (this.currentPage > 1)

this.showPage(this.currentPage - 1);

}

this.next = function() {

if (this.currentPage < this.pages) {

this.showPage(this.currentPage + 1);

}

}

this.init = function() {

var rows = document.getElementById(tableName).rows;

var records = (rows.length - 1);

this.pages = Math.ceil(records / itemsPerPage);

this.inited = true;

}

this.showPageNav = function(pagerName, positionId) {

if (! this.inited) {

alert("not inited");

return;

}

var element = document.getElementById(positionId);

var pagerHtml = '<span onclick="' + pagerName + '.prev();" class="pg-normal"> ?Prev </span> ';

for (var page = 1; page <= this.pages; page++)

pagerHtml += '<span id="pg' + page + '" class="pg-normal" onclick="' + pagerName + '.showPage(' + page + ');">' + 

page + '</span> ';

pagerHtml += '<span onclick="'+pagerName+'.next();" class="pg-normal"> Next ?/span>';

element.innerHTML = pagerHtml;

}

}

</script>

Answer 1

我已经很长时间没有这样做了，但是你可以像这样包装你的脚本:

<script type="javascript">
    //<![CDATA[

    //Your JS Code

    //]]>
</script>

这将阻止 W3C 验证器将您的 JS 解析为标记。