javascript - 使用jquery获取与json对象中提供的值匹配的对象？

Question

我有一个 json 对象，如下所示，并且我的 json 对象中有“skus”值的随机参数

喜欢

     var mytestvalue="Fit:Regular,Color:Coyote (120)"; or
      var mytestvalue="Color:Coyote (120),Fit:Regular"; 


     [
       {
            "index":0,
        "title":"Foo1",
        "skus":"Fit:Regular,Size:6,Color:Coyote (120)",
   },
   {
        "index":1,
        "title":"Foo2",
        "skus":"Fit:Regular,Color:Coyote (120),Size:65",
   },
   {
        "index":2,
        "title":"Foo3",
        "skus":"Fit:Regular,Size:7,Color:Coyote (120)",
   },
   {
        "index":0,
        "title":"Foo4",
        "skus":"Color:Coyote (120),Fit:Regular,Size:7.5",
       },
       {
        "index":1,
        "title":"Foo5",
        "skus":"Fit:Slim,Size:8,Color:Coyote (120)",
       },
   {
        "index":2,
        "title":"Foo6",
        "skus":"Fit:Regular,Size:9,Color:Coyote (120)",
   },
   { 
        "index":0,
        "title":"Foo7",
        "skus":"Fit:Regular,Size:8.5,Color:Coyote (120)",
  },
  {
        "index":1,
        "title":"Foo8",
        "skus":"Fit:Regular,Size:10,Color:Coyote (120)",
 },
 {
        "index":2,
    "title":"Foo9",
        "skus":"Fit:Slim,Color:Coyote (120),Size:13",
 },
 {
        "index":0,
        "title":"Foo10",
        "skus":"Fit:Regular,Size:8.5,Color:Coyote (120)",
 },
{
        "index":1,
        "title":"Foo11",
        "skus":"Fit:Regular,Size:10,Color:Coyote (120)",
},
{
        "index":2,
        "title":"Foo12",
        "skus":"Fit:Regular,Color:Coyote (120),Size:13",
}
    ]

我编写了一个函数来获取 sku 与我拥有的变量的匹配组合

   function getSkuCombinations(obj,prodskuval) {
     var combres = $.grep(obj, function (o) { //Will give you all the matches
            return o.SKUOptions.indexOf(prodskuval) > -1;
     });
     return combres;
}

我这样称呼这个函数

     var combinationresults=getSkuCombinations(myobj,mytestvalue)

当我这样做时，我应该得到所有具有我通过的组合“mytestvalue”的sku，但这个函数现在只返回我

       var myresult= [{
                "index":1,
                "title":"Foo2",
                "skus":"Fit:Regular,Color:Coyote (120),Size:65",
                  }]

谁能帮我做这件事

这个功能解决了我的问题，

     function getSkuCombinations(obj,prodskuval) {
          var combres = $.grep(obj, function (o) { //Will give you all the matches
                var newskus=o.skus.split(',').sort().join(',');             
                var newprdskus=prodskuval.split(',').sort().join(',');             
                    return newskus.indexOf(newprdskus) > -1;
         });
    }

Answer 1

var checkSKU = function (obj, testValue) {
    var results = [];
    obj.forEach(function (item) {
        if (item.skus.indexOf(testValue) > -1) {
            results.push(item);
        }
    });
    return results;
};

JSFiddle 测试用例:http://jsfiddle.net/N9V9q/3/