ansible - 从变量创建字典键并添加 IP 列表作为值

Question

我想创建一个字典并用变量键和值填充。这些值将是 IP 列表。
如果字典中已经存在该键，那么我需要将 IP 添加到现有列表中。

这里是输入数据，它是一个列表的列表。

parse1.json:

[
    [
        "/RAD33G4099/mobile_app/pl_crad.la-dc.vivo.com_80",
        "properties",
        "members",
        "/Common/10.50.100.25:80",
        "session"
    ],
    [
        "/RAD33G4099/mobile_app/pl_crad.la-dc.vivo.com_80",
        "properties",
        "members",
        "/Common/10.50.100.39:80",
        "session"
    ],
    [
        "/RAD33G4099/mobile_app/pl_crad.la-dc.vivo.com_80",
        "properties",
        "members",
        "/Common/10.50.100.49:80",
        "session"
    ],
    [
        "/RAD33G4099/mobile_app/pl_crad.la-dc.vivo.com_443",
        "properties",
        "members",
        "/Common/10.50.100.18:80",
        "session"
    ],
    [
        "/RAD33G4099/mobile_app/pl_crad.la-dc.vivo.com_443",
        "properties",
        "members",
        "/Common/10.50.100.28:80",
        "session"
    ],
    [
        "/RAD33G4099/mobile_app/pl_crad.la-dc.vivo.com_443",
        "properties",
        "members",
        "/Common/10.50.100.48:80",
        "session"
    ]
]

这是我解决这个问题的尝试:

 - set_fact:
     my_dic: {} 
     disabled_host: "{{ lookup('file', 'parse1.json')   }}"  

 - name: add new key / value pairs to dict
      set_fact:
        my_dict_var: "{{ my_dict_var + [ my_dic | combine ( { name + '_' +  app_name : host } ,  recursive=True) ] }}"
      loop: "{{ disabled_host }}"
      vars:
        name: "{{ item[0]  | regex_replace('^\/.*\/(.*)$', '\\1') }}"
        app_name: "{{ item[0] | regex_replace('^\/.*\/(.*)\/.*$', '\\1')  }}"
        host: "{{ item[3] | regex_replace('^\/.*\/(.*):.*$', '\\1')  }}"

实际输出是

ok: [localhost] => {
    "msg": [
        {
            "pl_crad.la-dc.vivo.com_80_mobile_app": "10.50.100.25"
        },
        {
            "pl_crad.la-dc.vivo.com_80_mobile_app": "10.50.100.39"
        },
        {
            "pl_crad.la-dc.vivo.com_80_mobile_app": "10.50.100.49"
        },
        {
            "pl_crad.la-dc.vivo.com_443_mobile_app": "10.50.100.18"
        },
        {
            "pl_crad.la-dc.vivo.com_443_mobile_app": "10.50.100.28"
        },
        {
            "pl_crad.la-dc.vivo.com_443_mobile_app": "10.50.100.48"
        }
    ]
}

但是，如果 key 相同，我想创建一个 IP 列表。

我想要的输出是

{
  "pl_crad.la-dc.vivo.com_80_mobile_app": [ 
    "10.50.100.25", 
    "10.50.100.39", 
    "10.50.100.49" 
  ],
  "pl_crad.la-dc.vivo.com_443_mobile_app": [ 
    "10.50.100.18",
    "10.50.100.28", 
    "10.50.100.48"
  ]
}

Answer 1

您不必采取困难的方式并使用正则表达式，您可以只 split这些字符串，和/或，使用 basename and dirname .

• 使用dirname和basename:

  - set_fact:
    disabled_hosts_ips: >-
      {{
        disabled_hosts_ips | default({})
        | combine({
          name: (disabled_hosts_ips | default({}))[name] | default([]) 
            + [ip] 
        })
      }}
    loop: "{{ disabled_hosts }}"
    vars:
      name: "{{ item[0] | basename ~ '_' ~ item[0] | dirname | basename }}"
      ip: "{{ (item[3] | basename).split(':')[0] }}"
  

• 使用分割:

  - set_fact:
    disabled_hosts_ips: >-
      {{
        disabled_hosts_ips | default({})
        | combine({
          name: (disabled_hosts_ips | default({}))[name] | default([]) 
            + [ip]
        })
      }}
    loop: "{{ disabled_hosts }}"
    vars:
      name: "{{ item[0].split('/')[-2:] | reverse | join('_') }}"
      ip: "{{ item[3].split('/')[-1].split(':')[0] }}"
  

两者都给出:

disabled_hosts_ips:
  pl_crad.la-dc.vivo.com_443_mobile_app:
  - 10.50.100.18
  - 10.50.100.28
  - 10.50.100.48
  pl_crad.la-dc.vivo.com_80_mobile_app:
  - 10.50.100.25
  - 10.50.100.39
  - 10.50.100.49