c# - 如何将匿名类型传递给函数，然后获取值

Question

我有一个像这样的函数:

private void DropIncompleteQuarters(//what goes in here? This? IEnumerable<dynamic> gb)
{
    foreach(var groupInGb in gb)
    {
        // What goes in here to get each element?
    }
}

我正在生成一个分组，如下所示:

histData = new List<OHLC>();

var gb = histData.GroupBy(o => new
{
    Year = o.Date.Year,
    Quarter = ((o.Date.Month - 1) / 3) + 1
})
.ToDictionary(g => g.Key, g => g.ToList());

我想将 gb 传递给 DropIncompleteQuarters，但我不确定 type 应该是什么。

然后在 DropIncompleteQuarters 内部，我想迭代 items？

Answer 1

我建议使用命名元组而不是匿名类型。通过轻微的语法更改 - (...) 而不是 {...} 您可以输入

private void DropIncompleteQuarters(Dictionary<(int Year, int Quarter), 
                                               List<OHLC>> gb)
{
    foreach (var pair in gb)
    {
        // Let's deconstruct pair.Key 
        var (year, quarter) = pair.Key; 
        var list = pair.Value;

        //TODO: some logic for year and quarter and list
    }
}

histData = new List<OHLC>();

var gb = histData
   .GroupBy(o => ( // change { .. } to ( .. ) and `=` to `:`
      Year    : o.Date.Year,
      Quarter : ((o.Date.Month - 1) / 3) + 1
   ))
   .ToDictionary(g => g.Key, g => g.ToList());