javascript - 如何将表单内容从 JavaScript 转换为 PHP？-6ren

javascript - 如何将表单内容从 JavaScript 转换为 PHP？

转载作者：行者123 更新时间：2023-12-02 17:35:46

我正在尝试将内容从 JavaScript 获取到 php。基本上，我想从下拉菜单中获取 $category 和 $subcategory 中选定值的 List1 和 List2。我根本不懂 javascript，所以这可能是我想做的一件非常基本的事情。

        <script type="text/javascript">

var categories = [];categories["startList"] = ["Apparel","Books"]
categories["Apparel"] = ["Men","Women"];
categories["Books"] = ["Biography","Fiction","Nonfiction"];
categories["Men"] = ["Shirts","Ties","Belts"];
categories["Women"] = ["Blouses","Skirts","Scarves"];
categories["Biography"] = ["Contemporay","Historical","Other"];
categories["Fiction"] = ["Science","Romance"];

var nLists = 2; // number of lists in the set

function fillSelect(currCat,currList){
var step = Number(currList.name.replace(/\D/g,""));
for (i=step; i<nLists+1; i++) {
document.forms[0]['List'+i].length = 1;
document.forms[0]['List'+i].selectedIndex = 0;
}
var nCat = categories[currCat];
for (each in nCat)  {
var nOption = document.createElement('option'); 
var nData = document.createTextNode(nCat[each]); 
nOption.setAttribute('value',nCat[each]); 
nOption.appendChild(nData); 
currList.appendChild(nOption); 
} 
}

function getValue(L2, L1) {
alert("Your selection was:- \n" + L1 + "\n" + L2 );
}

function init() {
fillSelect('startList',document.forms[0]['List1'])
}

navigator.appName == "Microsoft Internet Explorer" ? attachEvent('onload', init, false) : addEventListener('load', init, false);    

</script>
</head>

<body>
<form action="">
<select name='List1' onchange="fillSelect(this.value,this.form['List2'])">
<option selected>Make a selection</option>
</select>

&nbsp;
<select name='List2' onchange="getValue(this.value,this.form['List1'].value)">
<option selected >Make a selection</option>
</select>
</form>

</body>
</html>
.
.


input type="Submit" name="Send" value="Search">
</form>

</body>
</html>
<?php

$response = array();
require_once 'Test21/funciones_bd.php';
$db = new funciones_BD();
    $category = $_POST["List1"];
    $subcategory = $_POST["List2"];
.
.
.
?>