javascript - 读取、搜索和排序所有 CSV 值，避免重复

Question

我有以下 CSV:

Title, Rating, Year, Genre
All Quiet on the Western Front,8.1,1930,"Drama , War"
Gone with the Wind,8.2,1939,"Drama , Romance , War"
The Wizard of Oz,8.2,1939,"Adventure , Family , Fantasy , Musical"
Fantasia,7.9,1940,"Animation , Family , Fantasy , Music"
Pinocchio,7.6,1940,"Animation , Adventure , Drama , Family , Fantasy , Music"
The Great Dictator,8.5,1940,"Comedy , Drama , War"
Citizen Kane,8.5,1941,"Drama , Mystery"
Dumbo,7.3,1941,"Animation , Family , Musical"
Bambi,7.4,1942,"Animation , Drama , Family"
Casablanca,8.7,1942,"Drama , Romance , War"
It's a Wonderful Life,8.7,1946,"Drama , Family , Fantasy"
Notorious,8.2,1946,"Drama , Film-Noir , Romance , Thriller"
All About Eve,8.4,1950,Drama
Cinderella,7.3,1950,"Animation , Family , Fantasy , Musical , Romance"
Alice in Wonderland,7.4,1951,"Animation , Adventure , Family , Fantasy , Musical"
Strangers on a Train,8.2,1951,"Crime , Film-Noir , Thriller"
Dial M for Murder,8.2,1954,"Crime , Thriller"
Knock on Wood,7,1954,Comedy
Seven Samurai,8.8,1954,"Action , Drama"
Lady and the Tramp,7.4,1955,"Animation , Adventure , Comedy , Family , Romance"
Rebel Without a Cause,7.8,1955,"Drama , Romance"
The Trouble with Harry,7.2,1955,"Comedy , Mystery"
Forbidden Planet,7.7,1956,"Action , Adventure , Sci-Fi"
The Ten Commandments,7.9,1956,"Adventure , Drama , History"
12 Angry Men,8.9,1957,Drama

我想要完成的是这个(我的头现在不能正常工作):

读取 CSV 并创建一个仅显示所有独特类型的数组(例如:戏剧、 war 、奇幻......而不重复数组中的类型)

在 CSV 中搜索具有特定流派的行。例如，如果我搜索“戏剧”，则只会显示第 4 列中具有“戏剧”值的行。 (不显示流派列)

按标题、评级或年份对 CSV 进行排序(不显示类型列)。

我正在通过以下方式读取 CSV:

$.ajax({
        type: "GET",
        url: "movies.csv",
        dataType: "text",
        success: function(data) {
            var results = $.parse(data);
        }
     });

如果我执行 alert(JSON.stringify(results, null, 4)) ，它将打印正确的信息。 JSON 对象如下所示:

{
  "results": {
    "fields": [
      "Title",
      " Rating",
      " Year",
      " Genre"
    ],
    "rows": [
      {
        "Title": "All Quiet on the Western Front",
        " Rating": 8.1,
        " Year": 1930,
        " Genre": "Drama , War"
      },
      {
        "Title": "Gone with the Wind",
        " Rating": 8.2,
        " Year": 1939,
        " Genre": "Drama , Romance , War"
      },
      {
        "Title": "The Wizard of Oz",
        " Rating": 8.2,
        " Year": 1939,
        " Genre": "Adventure , Family , Fantasy , Musical"
      },
      {
        "Title": "Fantasia",
        " Rating": 7.9,
        " Year": 1940,
        " Genre": "Animation , Family , Fantasy , Music"

所以我知道这部分正在发挥作用。我正在尝试创建一个数组，然后用流派值填充 SELECT 标记。然后，如果用户选择其中之一，它将再次搜索文件，但仅显示指定了流派的行。用户将能够按前 3 列对列表进行排序。我现在问这个问题是因为我的头(和视力)现在不太好。

Answer 1

类型选择

http://jsfiddle.net/coma/4N676/25/

var movies = new Movies(JSON.parse(gists.files.Movies.content));
var html = '<option>Filter by genre</option>';

movies.getGenres().forEach(function(genre) {

    html += '<option value="' + genre + '">' + genre + '</option>';
});

$('#genre')
    .html(html)
    .change(function() {

        var list = movies
            .reset()
            .filterByGenre(this.value)
            .sortByTitleAsc()
            .getList();

        alert(JSON.stringify(list));
    });

http://jsfiddle.net/coma/4N676/

基础

var Movies = function(movies)
{
    var genres = [];
    var ratingMin = Infinity;
    var ratingMax = -1;
    var yearMin = Infinity;
    var yearMax = -1;

    movies.forEach(function(movie, movieIndex) {

        movie.Genre  = movie.Genre.split(', ');
        movie.Rating = parseFloat(movie.Rating);
        movie.Year = parseInt(movie.Year, 10);

        ratingMin = Math.min(movie.Rating, ratingMin);
        ratingMax = Math.max(movie.Rating, ratingMax);

        yearMin = Math.min(movie.Year, yearMin);
        yearMax = Math.max(movie.Year, yearMax);

        movie.Genre.forEach(function(genre, genreIndex) {

            genre = $.trim(genre).toLowerCase();
            movie.Genre[genreIndex] = genre;

            if (genres.indexOf(genre) < 0) {

                genres.push(genre);
            }

            genres.sort();
        });
    });

    this.original  = movies;
    this.list      = movies.slice();
    this.ratingMin = ratingMin;
    this.ratingMax = ratingMax;
    this.yearMin   = yearMin;
    this.yearMax   = yearMax;
    this.genres    = genres;
};

Movies.prototype.reset = function()
{
    this.list = this.original.slice();

    return this;
};

setter/getter

Movies.prototype.getList = function()
{
    return this.list.slice();
};

Movies.prototype.getRatingRange = function()
{
    return [this.ratingMin, this.ratingMax];
};

Movies.prototype.getRatingMax = function()
{
    return this.ratingMax;
};

Movies.prototype.getRatingMin = function()
{
    return this.ratingMin;
};

Movies.prototype.getYearRange = function()
{
    return [this.yearMin, this.yearMax];
};

Movies.prototype.getYearMax = function()
{
    return this.yearMax;
};

Movies.prototype.getYearMin = function()
{
    return this.yearMin;
};

Movies.prototype.getGenres = function()
{
    return this.genres.slice();
};

过滤器

Movies.prototype.filterByNumbers = function(property, number)
{
    if ($.isNumeric(number)) {

        this.list = this.list.filter(function(movie) {

            return movie[property] === number;
        });
    }

    if ($.isArray(number)) {

        this.list = this.list.filter(function(movie) {

            return movie[property] >= number[0]
                && movie[property] <= number[1];
        });
    }

    return this;
};

Movies.prototype.filterByGenre = function(genre)
{
    this.list = this.list.filter(function(movie) {

        return movie
            .Genre
            .indexOf(genre.toLowerCase()) >= 0;
    });

    return this;
};

Movies.prototype.filterByTitle = function(title)
{
    this.list = this.list.filter(function(movie) {

        return movie
            .Title
            .toLowerCase()
            .indexOf(title.toLowerCase()) >= 0;
    });

    return this;
};

Movies.prototype.filterByYear = function(year)
{ 
    this.filterByNumbers('Year', year);

    return this;
};

Movies.prototype.filterByRating = function(rating)
{ 
    this.filterByNumbers('Rating', rating);

    return this;
};

分拣机

Movies.prototype.sortAsc = function(property)
{ 
    this.list.sort(function(a, b) {

        return a[property] > b[property];
    });

    return this;
};

Movies.prototype.sortDesc = function(property)
{ 
    this.list.sort(function(a, b) {

        return a[property] < b[property];
    });

    return this;
};

Movies.prototype.sortByTitleAsc = function()
{ 
    this.sortAsc('Title');

    return this;
};

Movies.prototype.sortByTitleDesc = function()
{ 
    this.sortDesc('Title');

    return this;
};

Movies.prototype.sortByYearAsc = function()
{ 
    this.sortAsc('Year');

    return this;
};

Movies.prototype.sortByYearDesc = function()
{ 
    this.sortDesc('Year');

    return this;
};

Movies.prototype.sortByRatingAsc = function()
{ 
    this.sortAsc('Rating');

    return this;
};

Movies.prototype.sortByRatingDesc = function()
{ 
    this.sortDesc('Rating');

    return this;
};

使用

$.getJSON('https://api.github.com/gists/9803182', function(gists) {

    var movies = new Movies(JSON.parse(gists.files.Movies.content));

    movies
        .filterByGenre('comedy')
        .filterByYear([1954, 2000])
        .sortByTitleDesc();

    console.log('Filtered and sorted', movies.getList());
    console.log('Original', movies.reset().getList());
});