twitter - 如何在 Dart 中设置 OAuth 随机数

Question

现在，我用 dart 为 twitter 制作 OAuth 程序。

但是，我无法创建 oauth_nonce。

首先，我认为这段代码。

String create_nonce(){
    var rnd = new Random();
    int i = 0;
    var number = rnd.nextInt(pow(2,8*4));
    List<int> listi = UTF8.encode(number.toString());
    String str = "";
    while(i < 3){
        number = rnd.nextInt(pow(2,8*4)); 
        if(number < pow(2,8*4) - 1){
            number = rnd.nextInt(pow(2,8*4));
       }
       listi = UTF8.encode(number.toString());
       str = str + CryptoUtils.bytesToBase64(listi);
       i++;
    }
    return str;
}

但是，该方法无法创建预期的字符串。

Please tell me how to make a oauth_nonce.

Nonce The oauth_nonce parameter is a unique token your application should generate for each unique request. Twitter will use this value to determine whether a request has been submitted multiple times. The value for this request was generated by base64 encoding 32 bytes of random data, and stripping out all non-word characters, but any approach which produces a relatively random alphanumeric string should be OK here.

oauth_nonce kYjzVBB8Y0ZFabxSWbWovY3uYSQ2pTgmZeNu2VS4cg

Answer 1

import 'dart:math' as math;
import 'package:crypto/crypto.dart';


void main() {
  math.Random rnd = new math.Random();

  List<int> values = new List<int>.generate(32, (i) => rnd.nextInt(256));
  print(CryptoUtils.bytesToBase64(values));
}

产生

QqPlpI8BmDk9byWDqJ4tBCMMIWv24v4WL5KZsufnWqQ=

我不确定这到底意味着什么

and stripping out all non-word characters

我找到了https://dev.twitter.com/discussions/12445

You just want to make sure you're not sending characters like "!" "#" or "$" in your oauth_nonce. The process you've suggested sounds like it would work just fine.

.

Base64 includes '+' and '/'. You may need to stripping out them since they are non-word characters.

这样就可以了

import 'dart:math' as math;
import 'package:crypto/crypto.dart';

void main() {
  math.Random rnd = new math.Random();

  List<int> values = new List<int>.generate(32, (i) => rnd.nextInt(256));
  print(CryptoUtils.bytesToBase64(values).replaceAll(new RegExp('[=/+]'), ''));
}

替换replaceAll之前和之后

elrA+4rWr4O3zNv0L57iOLqTQD94abJ23hFoK+hk6QE=
elrA4rWr4O3zNv0L57iOLqTQD94abJ23hFoKhk6QE