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javascript - 无法获取按钮的ID

转载 作者:行者123 更新时间:2023-12-02 17:22:51 25 4
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请看下面的代码

<?php
//echo $this->Html->css(array('bootstrap', 'mark', 'style'));
echo $this->Html->script(array('timer','swfobject','bootstrap.min.js'));



?>
<style>
#hideall {
display: none;
opacity: 0.7;
position: fixed;
height: 100%;
width: 100%;
top: 0;
left: 0;
background: #000;
border: 1px solid #cecece;
z-index: 1;
vertical-align:middle;
text-align:center;
}

.removeCardflip{
transition: rotateY(0deg);
-webkit-transition: rotateY(0deg);
transition-duration: 0s;
}




/* SECTIONS */
.section {
clear: both;
padding: 0 10px 0 10px;
margin: 0px;
}


</style>


<div id="hideall">
<?php //echo $this->Html->image('progress.gif', array('alt' => 'Wait', 'style' => 'text-align:center; padding-top:200px;'));?>
</div>

<!--<div class="wrapper" style="border: 1px solid red; width: 100%;">-->
<div class="section group" style="margin-top: 50px;">
<div class="col span_3_of_3">
<h3 style="margin:0px; font-size:22px;">Play word game: </h3>
</div>
</div>


<div class="">
<div>
<div>
<span class="remainWords"><?php //echo count($words);?></span> oxxxxxxxxxxxxxxxf <?php //echo $totalWords;?>
</div>

<div>
<?php
echo $this->Html->image("comic_edit.png",
array(
"alt" => "Pareto List",
"id" => "paretoList",
'url' => "javascript:;"
)
);
?>
</div>
</div>
</div>




<div class="container"><div class="row">






<?php

$word="";

foreach($worddeck as $worcard)
{
?>
<div class="xy col-lg-3 col-md-4 col-sm-6 img-rounded" id="card1" style="width:250px; height:200px; background-color:grey; heiht:170px; margin: 10px 10px;">
<div id="enside1" >
<h1 data-pos="<?php //echo ; ?>" ><?php echo $worcard['unique_wordsforcards']['en_word']; $enSpell = $worcard['unique_wordsforcards']['en_word']; ?></h1>
</div>

<div id="ptside1" style="display:none;">

<?php echo $phonemer[$enSpell]; ?>
<p><?php echo $worcard['unique_wordsforcards']['hint']; ?></p>
</div>
<div id="cntrol1">
<button type="button" id="<?php $enSpell ?>" class="a btn btn-success mr5 btn-lg">Acertei</button>
<button type="button" id="2" class="e btn btn-danger mr5 btn-lg">Errei</button>
</div>
</div>
<?php
}
?>





</div></div>


<!-- jQuery (necessary for Bootstrap's JavaScript plugins) -->
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.0/jquery.min.js"></script>
<!-- Include all compiled plugins (below), or include individual files as needed -->
<script type="text/javascript">
$(document).ready(function(){


$( ".btn-danger" ).click(function(){
console.log("Red Button");
var toclose = $(this).parent().parent();
$.ajax({
url: "../img/media.jpg",
}).done(function() {
console.log( "The act has been done");
toclose.toggle();
});
});


$( ".btn-success" ).click(function(){
console.log("Red Button");
var toclose = $(this).parent().parent();
$.ajax({
url: "../img/media.jpg",
}).done(function() {
xxx($(this).attr('id'));
console.log( "The act has been done");
toclose.toggle();
});
});

$( ".xy" ).click(function(){

$(this).find("#enside1").toggle();
$(this).find("#ptside1").toggle();
console.log(this);
});

function xxx(id)
{
alert(id);
}

function increment()
{
$.ajax({
url: "http://localhost/cake2/flip2/correct",
}).done(function() {
console.log( "The act has been done");
toclose.toggle();
});

}

});


</script>

请考虑如何在 PHP 循环内生成这些按钮。

我正在尝试使用以下代码打印按钮的 ID。

 $( ".btn-success" ).click(function(){
console.log("Red Button");
var toclose = $(this).parent().parent();
$.ajax({
url: "../img/media.jpg",
}).done(function() {
xxx($(this).attr('id'));
console.log( "The act has been done");
toclose.toggle();
});
});

但是警报对话框是空的。这里出了什么问题?

最佳答案

您在错误的位置使用了$(this)。在ajax调用之前保存按钮的id并在ajax调用done()函数中使用。

$( ".btn-success" ).click(function(){
console.log("Red Button");
idOfButton = $(this).attr('id');
var toclose = $(this).parent().parent();
$.ajax({
url: "../img/media.jpg",
}).done(function() {
alert(idOfButton);
console.log( "The act has been done");
toclose.toggle();
});
});

您还可以在ajax调用之前保存事件源,然后使用它来获取事件源元素的id。

$( ".btn-success" ).click(function(){
console.log("Red Button");
eventSourceButton = $(this);
var toclose = $(this).parent().parent();
$.ajax({
url: "../img/media.jpg",
}).done(function() {
alert(eventSourceButton.attr('id'));
console.log( "The act has been done");
toclose.toggle();
});
});

关于javascript - 无法获取按钮的ID,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/23763225/

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