python-3.x - 如何裁剪矩形或正方形内的图像区域？

Question

首先，我拍摄照片，然后在其上绘制一个矩形。现在我只想裁剪矩形内的图像。我尝试绘制轮廓，但在我的情况下没有解决问题。我被卡住了。

import cv2
import numpy as np

img = cv2.imread("C:/Users/hp/Desktop/segmentation/abc.jpg", 0);
h, w = img.shape[:2]
kernel = np.ones((15,15),np.uint8)

e = cv2.erode(img,kernel,iterations = 2)
d = cv2.dilate(e,kernel,iterations = 1)
ret, th = cv2.threshold(d, 150, 255, cv2.THRESH_BINARY_INV)

mask = np.zeros((h+2, w+2), np.uint8)
# cv2.floodFill(th, mask, (200,200), 255); # position = (200,200)
out = cv2.bitwise_not(th)
out= cv2.dilate(out,kernel,iterations = 3)
cnt, h = cv2.findContours(out,cv2.RETR_TREE,cv2.CHAIN_APPROX_SIMPLE)
for i in range(len(cnt)):
            area = cv2.contourArea(cnt[i])
            if(area>100):
                  mask = np.zeros_like(img)
                  cv2.drawContours(mask, cnt, i, 255, -1)
                  x,y,w,h = cv2.boundingRect(cnt[i])
                  crop= img[ y:h+y,x:w+x]
                  cv2.imshow("snip",crop )
                  if(cv2.waitKey(0))==27:break

cv2.destroyAllWindows()

Answer 1

考虑到矩形是黑色的，并且这里没有连接其他大的黑色元素，因此是在内部裁剪矩形的代码:

import cv2
import numpy as np

img  = cv2.imread("abc.jpg", 0);
h, w = img.shape[:2]
# print(img.shape)
kernel = np.ones((3,3),np.uint8)

img2 = img.copy()
img2[img2!=0]=255 
img2 = 255 - img2
img2 = cv2.dilate(img2, kernel)
img2 = cv2.medianBlur(img2, 9)
img2 = cv2.medianBlur(img2, 9)


position = np.where(img2 !=0)
x0 = position[0].min()
x1 = position[0].max()
y0 = position[1].min()
y1 = position[1].max()

print(x0,x1,y0,y1)

result = img[x0:x1,y0:y1]
result = cv2.resize(result,(800,800))
# rect = cv2.resize(np.hstack((img,img2)),(1000,700))

cv2.imshow('anything', result)
cv2.waitKey(0)
cv2.destroyAllWindows()