javascript - 返回确认功能不起作用

Question

我用 php 动态生成一些按钮，如下所示:

<?php
while( $row = mysql_fetch_assoc( $result ) ){
    echo "<tr>
        <td><a href='updateproject.php?id=$row[ID]' class='btn btn-warning btn-mini'>
            <i class='icon-white icon-pencil'></i>
            </a>
            <a href='deleterow.php?del=$row[ID]' onclick='return confirm('You want to delete this?');' class='btn btn-danger btn-mini'>
            <i class='icon-white icon-remove'></i>
            </a>
        </td>
        <td>{$row['Projectname']}</td>
        <td>{$row['Personincharge']}</td>
        <td>{$row['Description']}</td>
        <td>{$row['CreationDate']}</td>
        <td>{$row['Location']}</td>                             
    </tr>\n";
}
?>

我尝试了很多方法，但都不起作用。没有警报到来。它刚刚被删除...

Answer 1

你的斜杠将会被破坏，因为它会认为语句以confirm('结尾。试试这个:

onclick=\"return confirm('You want to delete this?');\"