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python - Pandas 合并循环内生成的数据帧

转载 作者:行者123 更新时间:2023-12-02 17:16:11 25 4
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假设我有这样的数据框(在循环内生成并添加到列表中):

column  row data_503    plate
0 1 A 1 2
1 1 B 2 2
2 1 C 3 2
3 1 D 4 2

column row data_280 plate
0 1 A 1 2
1 1 B 2 2
2 1 C 3 2
3 1 D 4 2

column row data_503 plate
0 1 A 1 1
1 1 B 2 1
2 1 C 3 1
3 1 D 4 1

column row data_280 plate
0 1 A 1 1
1 1 B 2 1
2 1 C 3 1
3 1 D 4 1

我确实有一个布局文件,它将测量值映射到特定条件:

column  row cond    plate
0 1 A 5 1
1 1 B 5 1
2 1 C 5 1
3 1 D 4 1
0 1 A 5 2
1 1 B 5 2
2 1 C 5 2
3 1 D 4 2

我可以像这样组合数据框:

for df in df_list:
layout= pd.merge(layout, df, on=['plate', 'row', 'column'], how = 'outer')

但是,我总是得到 data_280_xdata_280_y 列,但我只想获得 data_280data_503列。将 outer 更改为 left 不会改变任何内容。

有什么办法可以得到类似的东西吗?:

column  row cond    plate    data_280    data_503
0 1 A 5 1 1 1
1 1 B 5 1 2 2
2 1 C 5 1 3 3
3 1 D 4 1 4 4
0 1 A 5 2 1 1
1 1 B 5 2 2 2
2 1 C 5 2 3 3
3 1 D 4 2 4 4

最佳答案

您可以组合 _x_y 列,因为它们不会有任何重叠值(基于该布局 df),如下所示:

df['data_208'] = df['data_208_x'] + df['data_208_y']

然后您可以删除 _x_y 列。

用例子更新:

df1 = pd.DataFrame({"column": [1, 1, 1, 1], "row": ["A", "B", "C", "D"], "plate": [1, 1, 1, 1], "data_503": [4, 5, 6, 7]})
df2 = pd.DataFrame({"column": [1, 1, 1, 1], "row": ["A", "B", "C", "D"], "plate": [1, 1, 1, 1], "data_280": [1, 2, 3, 4]})
df3 = pd.DataFrame({"column": [1, 1, 1, 1], "row": ["A", "B", "C", "D"], "plate": [2, 2, 2, 2], "data_503": [4, 5, 6, 7]})
df4 = pd.DataFrame({"column": [1, 1, 1, 1], "row": ["A", "B", "C", "D"], "plate": [2, 2, 2, 2], "data_280": [1, 2, 3, 4]})
layout = pd.DataFrame({"column": [1, 1, 1, 1, 1, 1, 1, 1], "row": ["A", "B", "C", "D", "A", "B", "C", "D"], "cond": [5, 5, 5, 4, 5, 5, 5, 4], "plate": [1, 1, 1, 1, 2, 2, 2, 2]})

out = []
for df in [df1, df2, df3, df4]:
_ = pd.merge(layout, df, on=['column', 'row', 'plate'], how='outer').dropna()
out.append(_)

merged = out[0]
for df in out[1:]:
merged = pd.merge(merged, df, on=['column', 'row', 'plate', 'cond'], how='outer')

merged = merged.fillna(0)

merged['data_280'] = merged['data_280_x'] + merged['data_280_y']
merged['data_503'] = merged['data_503_x'] + merged['data_503_y']

merged = merged.drop(['data_280_x','data_280_y','data_503_x','data_503_y'],1)

给我:

column  cond  plate row  data_280  data_503
0 1 5 1 A 1.0 4.0
1 1 5 1 B 2.0 5.0
2 1 5 1 C 3.0 6.0
3 1 4 1 D 4.0 7.0
4 1 5 2 A 1.0 4.0
5 1 5 2 B 2.0 5.0
6 1 5 2 C 3.0 6.0
7 1 4 2 D 4.0 7.0

关于python - Pandas 合并循环内生成的数据帧,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/46179021/

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