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javascript - 当 ($(#addData).is( :"visible")) 时禁用表列排序

转载 作者:行者123 更新时间:2023-12-02 17:05:06 24 4
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只要 #addData 可见,我想禁用表列排序但是当我将 if ($("#addData").is(":hidden")) 应用于 .each() 函数时,它不起作用。

有办法吗?

这是表格排序代码:

$('th:contains(Remote), th:contains(Interval),th:contains(Last), th:contains(Active)')
.each(function(){

var th = $(this),
thIndex = th.index(),
inverse = false;

th.click(function(){

table.find('td').filter(function(){

return $(this).index() === thIndex;

}).sortElements(function(a, b){

return $.text([a]) > $.text([b]) ?
inverse ? -1 : 1
: inverse ? 1 : -1;

}, function(){

// parentNode is the element we want to move
return this.parentNode;

});

inverse = !inverse;

});

});


jQuery.fn.sortElements = (function(){

var sort = [].sort;

return function(comparator, getSortable) {

getSortable = getSortable || function(){return this;};

var placements = this.map(function(){

var sortElement = getSortable.call(this),
parentNode = sortElement.parentNode,

// Since the element itself will change position, we have
// to have some way of storing its original position in
// the DOM. The easiest way is to have a 'flag' node:
nextSibling = parentNode.insertBefore(
document.createTextNode(''),
sortElement.nextSibling
);

return function() {

if (parentNode === this) {
throw new Error(
"You can't sort elements if any one is a descendant of another."
);
}

// Insert before flag:
parentNode.insertBefore(this, nextSibling);
// Remove flag:
parentNode.removeChild(nextSibling);

};

});

return sort.call(this, comparator).each(function(i){
placements[i].call(getSortable.call(this));
});

};

})();

最佳答案

将可见性检查添加到当天调用的点击事件中。如果您将#addData 存储在每个变量中,则可以提高性能。

$('th:contains(Remote), th:contains(Interval),th:contains(Last), th:contains(Active)')
.each(function(){

var th = $(this),
thIndex = th.index(),
inverse = false;
//BOOSTIE: var addData = $('#addData');
th.click(function(){
//BOOSTIE: if(addData.is(':hidden'))
if($("#addData").is(":hidden")) //Check to see if its visible
{
table.find('td').filter(function(){

return $(this).index() === thIndex;

}).sortElements(function(a, b){

return $.text([a]) > $.text([b]) ?
inverse ? -1 : 1
: inverse ? 1 : -1;

}, function(){

// parentNode is the element we want to move
return this.parentNode;

});

inverse = !inverse;
}
});

});

关于javascript - 当 ($(#addData).is( :"visible")) 时禁用表列排序,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/25319485/

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