javascript - 如何从已排序的数组中找到最大的元素？

Question

我有三个排序数组，我需要从这些数组中找到前五个“5”元素。我能够找到前两个元素最大元素。我如何找到其他元素？

你能建议我们如何找到其他 3 个元素吗？

这是我的代码

 var maxArray=[];
        var array1=[2,7,12,23,40,44,67,88,102]
        var array2=[3,12,14,17,23,40,41,67,108]
        var array3=[8,12,23,40,59,86,119,130]
        var firstMax=array1[array1.length-1];
        var secondMax=array2[array2.length-1];


        alert(array1[array1.length-1]);
        if(array1[array1.length-1]>array2[array2.length-1] && array1[array1.length-1]>array3[array3.length-1]){

            maxArray.push(array1[array1.length-1]) ;
            firstMax=array1[array1.length-1];
            if(array2[array2.length-1]>array3[array3.length-1]){
                secondMax=array2[array2.length-1];
            }else {
                secondMax=array3[array3.length-1];

            }
        }else if(array2[array2.length-1]>array1[array1.length-1]&& array2[array2.length-1]>array3[array3.length-1]){
            maxArray.push(array1[array2.length-1])
            firstMax=array2[array2.length-1];

            if(array1[array1.length-1]>array3[array3.length-1]){
                secondMax=array1[array1.length-1];
            }else {
                secondMax=array3[array3.length-1];

            }

        }else{
            maxArray.push(array3[array3.length-1])
            firstMax=array3[array3.length-1];

            if(array2[array2.length-1]>array1[array1.length-1]){
                secondMax=array2[array2.length-1];
            }else {
                secondMax=array1[array1.length-1];

            }

        }
        maxArray.push(secondMax)

        alert(maxArray)

fiddle http://jsfiddle.net/9vsjm8uh/

Answer 1

jsFiddle (是的，没有 jQuery 就更好了，谢谢@Rajacsp)

var array1 = [2, 7, 12, 23, 40, 44, 67, 88, 102]
var array2 = [3, 12, 14, 17, 23, 40, 41, 67, 108]
var array3 = [8, 12, 23, 40, 59, 86, 119, 130]

var flatArray = array1.concat(array2).concat(array3);

flatArray.sort(function sortNumber(a, b) { return b - a; });
var maxArray = flatArray.slice(0, 5);

alert(maxArray); // 130,119,108,102,88