javascript - Angularjs: Controller 中的 $filter 返回的数据仍然与原始对象绑定(bind)

Question

我是 AngularJS 的新手，我决定通过尝试制作一个家谱应用程序/SPA 来开始学习。出于测试目的，我将家谱数据硬编码到 $scope.personRegister 中。我想做的第一件事是正确定位 personRegister 中的所有人员/节点，使用 ng-style 指令一次加载它们。

我在 Controller 内使用$filter，只返回第1000代中的人，并将过滤结果存储在名为test的新对象中。然后，我打算将数据传递到应用程序外部的方法上，以定位节点。

问题是，当我操作 test 中的数据时，它也会操作 $scope.personRegister 中的原始数据，因此 View 也会更新。为什么会出现这种情况？

<!-- borderbox is the subwindow -->
<div class="borderBox" style="left: 0px; top: 0px" ng-app="famTreeApp">

    <!-- the content of the borderbox -->
    <div class="insideContent" style="left: 100px; top: 0px">

        <div ng-controller="famTree">
            <div class="personBox" ng-repeat="name in personRegister"
            ng-style="{'left':name.posX+'px', 'top':name.posY+'px' }">
                {{name.fName}}
            </div>

        </div>

    </div>

</div>

var familyTreeApp = angular.module("famTreeApp", []);

familyTreeApp.controller("famTree", function($scope, $filter, $log) {
//temp hard-coded data
$scope.personRegister = [
                           {id:1, genId:1000, gender:'M', fName:'John', momId:4, dadId:3,  posX:'0',  posY:'0' },
                            {id:2, genId:1000, gender:'F', fName:'Lisa', momId:4, dadId:3,  posX:'0',  posY:'0' },
                            {id:3, genId:999, gender:'M', fName:'Mark', momId:6, dadId:5,  posX:'0',  posY:'0' },
                            {id:4, genId:999, gender:'F', fName:'Sarah', momId:8, dadId:7,  posX:'0',  posY:'0' },
                            {id:5, genId:998, gender:'F', fName:'Martha', momId:0, dadId:0,  posX:'0',  posY:'0' },
                            {id:6, genId:998, gender:'M', fName:'James', momId:0, dadId:0,  posX:'0',  posY:'0' },
                            {id:7, genId:998, gender:'M', fName:'Frederick', momId:0, dadId:0,  posX:'0',  posY:'0' },
                            {id:8, genId:998, gender:'F', fName:'Georgiana', momId:0, dadId:0,  posX:'0',  posY:'0' },
                            {id:9, genId:1000, gender:'M', fName:'Trevor', momId:11, dadId:10,  posX:'0',  posY:'0' },      
                            {id:10, genId:999, gender:'M', fName:'Andre', momId:8, dadId:7,  posX:'0',  posY:'0' },
                            {id:11, genId:999, gender:'F', fName:'Teresa', momId:0, dadId:0,  posX:'0',  posY:'0' },
                            {id:12, genId:1000, gender:'F', fName:'Shakira', momId:4, dadId:3,  posX:'0',  posY:'0' }
];
$scope.spouseRegister = [
                            {husbandId:3, wifeId:4, haveKids:1, currMarried:1},
                            {husbandId:6, wifeId:5, haveKids:1, currMarried:0},
                            {husbandId:7, wifeId:8, haveKids:1, currMarried:1},
                            {husbandId:10, wifeId:11, haveKids:1, currMarried:1}
];
    $scope.test = $filter('filter')($scope.personRegister, {genId: 1000});

    $log.log($scope.personRegister[1]); //message to console


    $scope.test[1].posX = 50;
    $scope.test[0].fName += 'ny Boy';

    $log.log($scope.test[1]); //message to console
    $log.log($scope.personRegister[1]); //message to console

    //personPostioner(test);

});

http://jsfiddle.net/kq8xduj6/2/

如有任何帮助，我们将不胜感激。

Answer 1

您的数组包含的对象与 $scope.personRegister 和 $scope.test 引用的对象相同。是的，$filter返回一个新数组，但数组的内容仍然是相同的对象。如果您希望它们是不同的数据集，请过滤掉原始数组的副本。

$scope.test = $filter('filter')(angular.copy($scope.personRegister), {genId: 1000});