Symfony/FOS - 将用户 id 变量传递给表单类型

Question

我尝试从 CategoryType 表单中设置“作者”字段的值。我希望它是使用 FOS bundle 登录的当前用户的用户 ID。

我的 CategoryType 表单:

namespace My\CategoryBundle\Form;

use Symfony\Component\Form\AbstractType;
use Symfony\Component\Form\FormBuilderInterface;
use Symfony\Component\OptionsResolver\OptionsResolverInterface;

class CategoryType extends AbstractType
{
    private $userId;

    public function __construct(array $userId)
    {
        $this->userId = $userId;
    }

     /**
     * @param FormBuilderInterface $builder
     * @param array $options
     */
    public function buildForm(FormBuilderInterface $builder, array $options)
    {
        $builder
            ->add('title')
            ->add('author')
            ->add('content')
        ;
    }

    /**
     * @param OptionsResolverInterface $resolver
     */
    public function setDefaultOptions(OptionsResolverInterface $resolver)
    {
        $resolver->setDefaults(array(
            'data_class' => 'My\CategoryBundle\Entity\Category',
            'auteur' => $this->userId
        ));
    }

    /**
     * @return string
     */
    public function getName()
    {
        return 'my_categorybundle_category';
    }
}

和我的 Controller 操作:

public function addAction()
{
    $category = new Category;
    $user = $this->get('security.context')->getToken()->getUser(); 
    $userId = $user->getId();

    $form = $this->get('form.factory')->create(new CategoryType(), array( 'author' => $userId));

    $request = $this->get('request');
    if ($request->getMethod() == 'POST') {
        $form->bind($request);

        if ($form->isValid()) {
            $em = $this->getDoctrine()->getManager();
            $em->persist($category);
            $em->flush();

        return $this->redirect($this->generateUrl('mycategory_voir',
            array('id' => $category->getId())));
        }
    }
    return $this->render('MyCategoryBundle:Category:add.html.twig',
        array(
            'form' => $form->createView(),
        ));
}

我在运行操作时发现此错误:

Catchable Fatal Error: Argument 1 passed to My\CategoryBundle\Form\CategoryType::__construct() must be an array, none given, called in /My/CategoryBundle/Controller/CategoryController.php on line 55 and defined in /My/CategoryBundle/Form/CategoryType.php line 13

我传递给表单的数组不是已经存在了吗？

Answer 1

你的问题就在这一行

$form = $this->get('form.factory')->create(new CategoryType(), array( 'author' => $userId));

您不满足 My\CategoryBundle\FormCategoryType::__construct() 的契约(Contract)。在这里，我们换个角度来看一下。

$form = $this->get('form.factory')->create(
    new CategoryType(/* You told PHP to expect an array here */)
  , array('author' => $userId)
);

作为第二个参数发送给 Symfony\Component\Form\FormFactory::create() 的数组最终会作为 $options 数组注入(inject) My\CategoryBundle\Form\CategoryType::buildForm()

据我所知，您有几种不同的方法可以解决此问题

1. 更新参数签名并调用 My\CategoryBundle\FormCategoryType::__construct() 来传递/接收整个用户对象(不仅仅是他们的 id - 请记住您正在工作此时与 Doctrine 关系，而不是它们映射到的较低级别的外键)

   namespace My\CategoryBundle\Form;
   
   use My\CategoryBundle\Entity\User; /* Or whatver your User class is */
   use Symfony\Component\Form\AbstractType;
   use Symfony\Component\Form\FormBuilderInterface;
   use Symfony\Component\OptionsResolver\OptionsResolverInterface;
   
   class CategoryType extends AbstractType
   {
       private $author;
   
       public function __construct( User $author )
       {
           $this->author = $author;
       }
   

   和

   $form = $this->get('form.factory')->create(
       new CategoryType(
         $this->get('security.context')->getToken()->getUser()
       )
   );
   

2. 不要将User注入(inject)到类型的构造函数中，只需让选项处理它

   namespace My\CategoryBundle\Form;
   
   use Symfony\Component\Form\AbstractType;
   use Symfony\Component\Form\FormBuilderInterface;
   use Symfony\Component\OptionsResolver\OptionsResolverInterface;
   
   class CategoryType extends AbstractType
   {
       private $userId;
   
        /**
        * @param FormBuilderInterface $builder
        * @param array $options
        */
       public function buildForm(FormBuilderInterface $builder, array $options)
       {
           $builder
               ->add('title')
               ->add('author', 'hidden', array('data'=>$options['author']))
               ->add('content')
           ;
       }
   
       /**
        * @param OptionsResolverInterface $resolver
        */
       public function setDefaultOptions(OptionsResolverInterface $resolver)
       {
           $resolver->setDefaults(array(
               'data_class' => 'My\CategoryBundle\Entity\Category'
           ));
       }
   
       /**
        * @return string
        */
       public function getName()
       {
           return 'my_categorybundle_category';
       }
   }
   

3. 甚至不用费心将作者放入表单并让 Controller 处理它

   $form = $this->get('form.factory')->create(
       new CategoryType()
     , array('author' => $this->get('security.context')->getToken()->getUser() )
   );
   

   和

   if ($request->getMethod() == 'POST') {
       $form->bind($request);
   
       if ($form->isValid()) {
           $category->setAuthor(
             $this->get('security.context')->getToken()->getUser()
           );
           $em = $this->getDoctrine()->getManager();
           $em->persist($category);
           $em->flush();
   
       return $this->redirect($this->generateUrl('mycategory_voir',
           array('id' => $category->getId())));
       }
   }
   

4. 将表单类型转换为服务并使用 DI 容器来注入(inject)安全上下文

   app/config/config.yml

   services:
     form.type.my_categorybundle_category:
       class: My\CategoryBundle\Form\CategoryType
       tags:
         - {name: form.type, alias: my_categorybundle_category}
       arguments: ["%security.context%"]
   

   更新您的类型以接收安全上下文

   namespace My\CategoryBundle\Form;
   
   use Symfony\Component\Security\Core\SecurityContext;
   use Symfony\Component\Form\AbstractType;
   use Symfony\Component\Form\FormBuilderInterface;
   use Symfony\Component\OptionsResolver\OptionsResolverInterface;
   
   class CategoryType extends AbstractType
   {
       private $author;
   
       public function __construct( SecurityContext $security )
       {
           $this->author = $security->getToken()->getUser();
       }
   

   然后在您的 Controller 中，使用其服务名称创建表单

   $form = $this->get('form.factory')->create('my_categorybundle_category');