gpt4 book ai didi

Scala Kleisli 在 IntelliJ 中抛出错误

转载 作者:行者123 更新时间:2023-12-02 16:35:46 25 4
gpt4 key购买 nike

尝试在 Scala 中为虚构的部分类型实现 Kleisli 类别(阅读 Bartosz Milewski 的“程序员的类别理论”,这是第 4 章的练习)

object Kleisli {
type Partial[A, B] = A => Option[B]

implicit class KleisliOps[A, B](f1: Partial[A, B]) {

def >=>[C](f2: Partial[B, C]): Partial[A, C] =
(x: A) =>
for {
y <- f1(x)
z <- f2(y)
} yield z

def identity(f: Partial[A, B]): Partial[A, B] = x => f(x)

}

val safeRecip: Partial[Double, Double] = {
case 0d => None
case x => Some(1d / x)
}

val safeRoot: Partial[Double, Double] = {
case x if x < 0 => None
case x => Some(Math.sqrt(x))
}

val safeRootRecip: Partial[Double, Double] = safeRoot.>=>(safeRecip)

safeRootRecip(1d)
safeRootRecip(10d)
safeRootRecip(0d)
}

IDE (IntelliJ) 没有显示任何错误,但是当我运行这段代码时,我得到:

Error:(27, 57) value >=> is not a member of $line5.$read.$iw.$iw.Kleisli.Partial[Double,Double]
val safeRootRecip: Partial[Double, Double] = safeRoot.>=>(safeRecip)

在隐式类之外定义 >=>=> 效果很好。可能是什么原因?

最佳答案

@sinanspd 是对的。在 Dotty 中,代码似乎可以编译: https://scastie.scala-lang.org/n17APWgMQkWqy93ct2cghw

手动解决

val safeRootRecip: Partial[Double, Double] = KleisliOps(safeRoot).>=>(safeRecip)

编译但编译器本身没有发现这个转换

Information: KleisliOps{<null>} is not a valid implicit value 
for App.safeRoot.type => ?{def >=> : ?} because:
type mismatch;
found : App.safeRoot.type (with underlying type App.Partial[Double,Double])
required: App.Partial[A,Double]
(which expands to) A => Option[Double]
val safeRootRecip: Partial[Double, Double] = safeRoot.>=>(safeRecip)

似乎没有推断类型参数 A

(顺便说一下,Martin Odersky 在这里解释了为什么语言中存在隐式转换会使类型推断变得更糟:https://contributors.scala-lang.org/t/can-we-wean-scala-off-implicit-conversions/4388)

尝试使 PartialB 协变,并且(特别是)与 A 协变(类似于 A = > Option[B]B 协变,与 A 协变)

type Partial[-A, +B] = A => Option[B]

然后代码似乎可以编译。

另一种解决方法是用类型类 (MyTransform) 和隐式转换 (X => Y, KleisliOps) 替换隐式转换 ( myConversion) 根据此类型类定义(sometimes 这有助于隐式转换)

trait MyTransform[X, Y] {
def transform(x: X): Y
}
implicit def myConversion[X, Y](x: X)(implicit mt: MyTransform[X, Y]): Y =
mt.transform(x)

type Partial[A, B] = A => Option[B]

implicit def partialToKleisliOps[A, B]: MyTransform[Partial[A, B], KleisliOps[A, B]] =
f1 => new KleisliOps(f1)
class KleisliOps[A, B](f1: Partial[A, B]) {
def >=>[C](f2: Partial[B, C]): Partial[A, C] =
(x: A) =>
for {
y <- f1(x)
z <- f2(y)
} yield z

def identity(f: Partial[A, B]): Partial[A, B] = x => f(x)
}

关于Scala Kleisli 在 IntelliJ 中抛出错误,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/62751493/

25 4 0
Copyright 2021 - 2024 cfsdn All Rights Reserved 蜀ICP备2022000587号
广告合作:1813099741@qq.com 6ren.com