symfony - FOSRestBundle: Controller 必须返回给定的响应(Array())

Question

我从 FOSRestBundle 开始。我添加了这个路由配置:

//Sermovi/Bundle/APIBundle/Resources/config/routing.yml    
sermovi_api_homepage:
        type: rest
        resource: Sermovi\Bundle\APIBundle\Controller\DefaultController

//app/config/routing.yml     
sermovi_api:
    type: rest
    prefix:   /api
    resource: "@SermoviAPIBundle/Resources/config/routing.yml"

还有这个 config.yml

fos_rest:
    routing_loader:
        default_format: json
    view:
        view_response_listener: true

sensio_framework_extra:
    view:
        annotations: false

这个 Controller :

namespace Sermovi\Bundle\APIBundle\Controller;

use Symfony\Bundle\FrameworkBundle\Controller\Controller;
use FOS\RestBundle\Controller\FOSRestController;
use Symfony\Component\HttpFoundation\Response;


class DefaultController extends FOSRestController
{
    public function getArticlesAction()
    {
        $em = $this->getDoctrine()->getManager();

        $entity = $em->getRepository('SermoviManagementBundle:Transaction')->find(776);

        return array(
            'entity' => $entity
        );
    }
}

我收到此错误:

[{"message":"The controller must return a response (Array(entity => Object(Sermovi\Bundle\ManagementBundle\Entity\Transaction)) given).","class":"LogicException","trace":[{"namespace":"","short_class":"","class":"","type":"","function":"","file":"/home/tirengarfio/workspace/sermovi/app/bootstrap.php.cache","line":2855,"args":[]},{"namespace":"Symfony\Component\HttpKernel","short_class":"HttpKernel","class":"Symfony\Component\HttpKernel\HttpKernel","type":"->","function":"handleRaw","file":"/home/tirengarfio/workspace/sermovi/app/bootstrap.php.cache","line":2817,"args":[["object","Symfony\Component\HttpFoundation\Request"],["string","1"]]},{"namespace":"Symfony\Component\HttpKernel","short_class":"HttpKernel","class":"Symfony\Component\HttpKernel\HttpKernel","type":"->","function":"handle","file":"/home/tirengarfio/workspace/sermovi/app/bootstrap.php.cache","line":2946,"args":[["object","Symfony\Component\HttpFoundation\Request"],["string","1"],["boolean",true]]},{"namespace":"Symfony\Component\HttpKernel\DependencyInjection","short_class":"ContainerAwareHttpKernel","class":"Symfony\Component\HttpKernel\DependencyInjection\ContainerAwareHttpKernel","type":"->","function":"handle","file":"/home/tirengarfio/workspace/sermovi/app/bootstrap.php.cache","line":2247,"args":[["object","Symfony\Component\HttpFoundation\Request"],["string","1"],["boolean",true]]},{"namespace":"Symfony\Component\HttpKernel","short_class":"Kernel","class":"Symfony\Component\HttpKernel\Kernel","type":"->","function":"handle","file":"/home/tirengarfio/workspace/sermovi/web/app_dev.php","line":28,"args":[["object","Symfony\Component\HttpFoundation\Request"]]}]}]

编辑:

“我可以”做下面这样的事情吗？或者由于 FOSRestBundle 使用 JMSSerializerBundle 我不应该这样做？

$serializedEntity = $this->container->get('serializer')->serialize($entity, 'json');
return new Response($serializedEntity);

Answer 1

有多种方法可以使用 FOSRestBundle 设置 Controller 。按照你这样做的方式，你必须返回一个 View 。这是 github 上的休息 Controller 的链接，可能会对您有所帮助。 LiipHelloBundle有一个例子。

此外，我发现使用ClassResourceInterface最简单。在我的 Controller 中。这样，我返回一个数组，它本身处理所有序列化。它还使用您的 Controller 名称来生成必要的路由，因此我不必手动定义任何路由。这是我设置 Controller 的首选方式。请参阅文档条目 here了解它是如何工作的。

如果您最终使用 ClassResourceInterface ，请确保为每个操作包含以下注释，它将使您返回的数组正确序列化:

use FOS\RestBundle\Controller\Annotations as Rest;
//.....

/**
* @Rest\View()
*/
public function cgetAction() {}

您甚至可以通过设置 Controller 的方式来做到这一点，但我以前没有尝试过。如果您这样做并且有效，请告诉我们。

更新

对于那些可能有兴趣使用 FOSRestBundle 而不使用 ClassResourceInterface 的人，问题中 Controller 操作的问题是它不返回 View 。这应该在操作中起作用:

class DefaultController extends FOSRestController
{
    public function getArticlesAction()
    {
        $em = $this->getDoctrine()->getManager();

        $entity = $em->getRepository('SermoviManagementBundle:Transaction')->find(776);
        $statusCode = 200;

        $view = $this->view($entity, $statusCode);
        return $this->handleView($view);
    }
}