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asp.net - 如何使用 Linq 获取 XML 元素的值(即使为空)

转载 作者:行者123 更新时间:2023-12-02 16:25:06 24 4
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请原谅我的愚蠢,我倾向于发现遍历 XML 过于复杂。

我在 VB 中使用 ASP.NET。

我有一个 XML 文档,其中包含我公司员工的所有详细信息...

<staff>
<staffName>Test Staff</staffName>
<staffTitle>Slave</staffTitle>
<staffDepartmentName>Finance</staffDepartmentName>
<staffOffice>London</staffOffice>
<staffEmail>t.staff@company.co.uk</staffEmail>
<staffPhone>0207 123 456</staffPhone>
<staffNotes>Working hours Mon to Thurs 9.15 - 5.15</staffNotes>
<staffBio></staffBio>
</staff>

正如您所看到的,某些节点并不总是包含所有员工的数据;只有董事才有传记。

我访问这样的值...

For Each staff In ( _
From matches In myXMLFile.Descendants("staff").Descendants("staffName") _
Where matches.Nodes(0).ToString.ToLower.Contains(LCase(search)) _
Order By matches.Value _
Select matches)
staffName = staff.Descendants("staffName").Nodes(0).ToString)
staffTitle = staff.Descendants("staffTitle").Nodes(0).ToString)
staffOffice = staff.Descendants("staffOffice").Nodes(0).ToString)
staffEmail = staff.Descendants("staffEmail").Nodes(0).ToString)
staffPhone = staff.Descendants("staffPhone").Nodes(0).ToString)
staffNotes = staff.Descendants("staffNotes").Nodes(0).ToString)
staffBio = staff.Descendants("staffBio").Nodes(0).ToString)

' Do something with that data...
Next

一旦到达staffBio,我收到一条错误消息“对象引用未设置到对象的实例”。显然是因为该节点不存在。

我的问题是,即使变量为空,如何将值分配给变量,而不必在每次赋值之前进行条件检查?

最佳答案

首先,myXMLFile.Descendants("staff").Descendants("staffName") 是多余的。 Descendants 返回 XDocumentXElement 内任何级别的所有元素。因此,myXMLFile.Descendants("staffName") 会给出相同的结果。

其次,您可以像这样使用 Element 属性和 Value 属性:

staffBio = staff.Element("staffBio").Value

staff 将只有一个 staffBio 元素,因此无需使用 Descendants 属性。 Value 是一个字符串,因此您不需要调用Value.ToString。如果元素为空,则 Value 将返回一个空字符串,这就是您要查找的内容!

第三,在 VB.NET 中有一种更好的(而且我认为更直接的)方法可以做到这一点。这是一个控制台应用程序,演示了我将如何执行此操作:

Module Module1

Sub Main()
Dim myXMLFile = <allStaff>
<staff>
<staffName>Test Staff</staffName>
<staffTitle>Slave</staffTitle>
<staffDepartmentName>Finance</staffDepartmentName>
<staffOffice>London</staffOffice>
<staffEmail>t.staff@battens.co.uk</staffEmail>
<staffPhone>0207 123 456</staffPhone>
<staffNotes>Working hours Mon to Thurs 9.15 - 5.15</staffNotes>
<staffBio></staffBio>
</staff>
<staff>
<staffName>Other Staff</staffName>
<staffTitle>Master</staffTitle>
<staffDepartmentName>IT</staffDepartmentName>
<staffOffice>Oxford</staffOffice>
<staffEmail>o.staff@battens.co.uk</staffEmail>
<staffPhone>0207 123 789</staffPhone>
<staffNotes></staffNotes>
<staffBio>Some guy.</staffBio>
</staff>
</allStaff>

Dim search = "Test"

Dim searchQuery = From staff In myXMLFile...<staff> _
Where staff.<staffName>.Value.Contains(search) _
Select si = New StaffInfo With {.Name = staff.<staffName>.Value, _
.Title = staff.<staffTitle>.Value, _
.Department = staff.<staffDepartmentName>.Value, _
.Office = staff.<staffOffice>.Value, _
.Email = staff.<staffEmail>.Value, _
.Phone = staff.<staffPhone>.Value, _
.Notes = staff.<staffNotes>.Value, _
.Bio = staff.<staffBio>.Value}

For Each staff In searchQuery
Console.WriteLine("Name: {0}", staff.Name)
Console.WriteLine("Title: {0}", staff.Title)
Console.WriteLine("Department: {0}", staff.Department)
Console.WriteLine("Office: {0}", staff.Office)
Console.WriteLine("Email: {0}", staff.Email)
Console.WriteLine("Phone: {0}", staff.Phone)
Console.WriteLine("Notes: {0}", staff.Notes)
Console.WriteLine("Bio: {0}", staff.Bio)
Console.WriteLine()
Next

Console.ReadLine()

End Sub

Private Class StaffInfo

Private _name As String
Public Property Name() As String
Get
Return _name
End Get
Set(ByVal value As String)
_name = value
End Set
End Property

Private _title As String
Public Property Title() As String
Get
Return _title
End Get
Set(ByVal value As String)
_title = value
End Set
End Property

Private _department As String
Public Property Department() As String
Get
Return _department
End Get
Set(ByVal value As String)
_department = value
End Set
End Property

Private _office As String
Public Property Office() As String
Get
Return _office
End Get
Set(ByVal value As String)
_office = value
End Set
End Property

Private _email As String
Public Property Email() As String
Get
Return _email
End Get
Set(ByVal value As String)
_email = value
End Set
End Property

Private _phone As String
Public Property Phone() As String
Get
Return _phone
End Get
Set(ByVal value As String)
_phone = value
End Set
End Property

Private _notes As String
Public Property Notes() As String
Get
Return _notes
End Get
Set(ByVal value As String)
_notes = value
End Set
End Property

Private _bio As String
Public Property Bio() As String
Get
Return _bio
End Get
Set(ByVal value As String)
_bio = value
End Set
End Property

End Class

End Module

如果您有 XML 的架构(.xsd 文件),则可以将该 xmlns 的引用导入到 VB 源文件中,这将为您提供编写 LINQ to XML 查询的智能感知。

(编辑:创建架构的快速方法是在 Visual Studio 中打开 XML 文件,然后从 XML 菜单中选择“创建架构”。)

有关更多信息和帮助,请查看 "How Do I" video series on LINQ by Beth Massi

关于asp.net - 如何使用 Linq 获取 XML 元素的值(即使为空),我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/2825886/

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