python - 在 Python 列表中查找子字符串

Question

我有一个这样的列表:

a = ['aaa/aa/aa/a001', 'aaa/aa/aa/a002', 'aaa/aa/aa/a003']

我想检索数字部分。我该怎么做？

Answer 1

import re

a = ['aaa/aa/aa/a001','aaa/aa/aa/a002','aaa/aa/aa/a003']

for elem in a:
    print (re.sub(r"[^0-9]","",elem))

输出:

001
002
003

或者，通过列表理解:

numbers = [re.sub(r"[^0-9]","",x) for x in a]

print (numbers)

输出:

['001', '002', '003']