python - 检查一个字符串是否至少包含列表中的两个字符串

Question

我想知道字符串中的列表中是否至少有 2 个单词。某些单词在列表中重复。我想在列表中的字符串中找到两个不同 单词。

我试过这个:

keywords = ["word1", "word1", "word1", "word2", "word3"]
r = "word4 word2 word1 word5"

for keyword in keywords:
    if keyword in r:
        for keyword2 in keywords:
            if keyword2 in r:
                if keyword2 != keyword:
                    status="ok"
                    print("here at least 2 words matching")
                    break

Answer 1

如果你把 csv 中的单词放在 set 中.然后，您可以使用“set.intersection()”来查找该字符串共有的所有单词。

keyword_set = set(keywords)
common = keyword_set.intersection(r.split())
if len(common) >= 2:
    print('Found:', common)

Tomerikoo 建议的一旦找到两个项目就中断的方法速度更快，并且可以更改为如果也找到两个相同的单词则停止。但即使有更多匹配项，它也只会打印前两个匹配项。这是一个简化版本:

# To find only unique words, use `words_found = set()`
words_found = []
for word in set(keywords):
    if word in r:
        # If words_found is a set, use `words_found.add(word)`
        words_found.append(word)
        if len(words_found) >= 2:
            print("Found:", words_found)
            break