python - 删除彩色图像的晕影滤镜

Question

我是 Python OpenCV 图像处理的新手。我想删除图像的边框/轮廓阴影，如下所示。我检查了' how to remove shadow from scanned images '这对我不起作用。这甚至可能吗？

Answer 1

你的边框/轮廓阴影问题让我想起了小插图过滤器。你可以看看这个question如果你想了解更多。所以基本上我们的任务是消除晕影滤镜的影响，然后增加亮度。

#####VIGNETTE
import cv2
import numpy as np

img = cv2.imread('Paris.jpg')
height, width = img.shape[:2]
original = img.copy()
# generating vignette mask using Gaussian kernels
kernel_x = cv2.getGaussianKernel(width, 150)
kernel_y = cv2.getGaussianKernel(height, 150)
kernel = kernel_y * kernel_x.T
mask = 255 * kernel / np.linalg.norm(kernel)

# applying the mask to each channel in the input image
for i in range(3):
    img[:, :, i] = img[:, :, i] * mask


cv2.imshow('Original', original)
cv2.imshow('Vignette', img)
cv2.waitKey(0)
cv2.destroyAllWindows()

对抗效果变化 img[:, :, i] = img[:, :, i] * mask至 img[:, :, i] = img[:, :, i] / mask


现在我们需要增加图像的亮度。为此，我们将图像转换为 HSV 并增加饱和度和值矩阵的值。要更详细地了解它，您可以引用此 article .

#THE FULL CODE
import cv2
import numpy as np

img = cv2.imread('shadow.jpg')
original = cv2.imread('bright.jpg')
height, width = img.shape[:2]
# generating vignette mask using Gaussian kernels
kernel_x = cv2.getGaussianKernel(width, 150)
kernel_y = cv2.getGaussianKernel(height, 150)
kernel = kernel_y * kernel_x.T
mask = 255 * kernel / np.linalg.norm(kernel)

test = img.copy()
for i in range(3):
    test[:, :, i] = test[:, :, i] / mask    

hsv = cv2.cvtColor(test, cv2.COLOR_BGR2HSV)
hsv = np.array(hsv, dtype = np.float64)
hsv[:,:,1] = hsv[:,:,1]*1.3 ## scale pixel values up or down for channel 1(Lightness)
hsv[:,:,1][hsv[:,:,1]>255]  = 255
hsv[:,:,2] = hsv[:,:,2]*1.3 ## scale pixel values up or down for channel 1(Lightness)
hsv[:,:,2][hsv[:,:,2]>255]  = 255
hsv = np.array(hsv, dtype = np.uint8)
test = cv2.cvtColor(hsv, cv2.COLOR_HSV2BGR)


cv2.imshow('Original_bright', original)
cv2.imshow('Original_dark', img)
cv2.imshow('Result', test)
cv2.waitKey(0)
cv2.destroyAllWindows()

结果与原始明亮图像进行了比较。



如果没有反向小插图过滤器，结果会是什么样子。