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我正在使用 python 中的 opencv 开发形状检测算法。
我正在使用库中的轮廓,并且成功检测出一些形状:圆形,矩形和三角形。
唯一的问题是,我只需要检测圆形的矩形和八边形。
此外,圈子还在运作,但不一致。
所以,这是我的代码:
import cv2
import numpy as np
def nothing(x):
# any operation
pass
cap = cv2.VideoCapture(1)
cv2.namedWindow("Trackbars")
cv2.createTrackbar("L-H", "Trackbars", 0, 180, nothing)
cv2.createTrackbar("L-S", "Trackbars", 66, 255, nothing)
cv2.createTrackbar("L-V", "Trackbars", 134, 255, nothing)
cv2.createTrackbar("U-H", "Trackbars", 180, 180, nothing)
cv2.createTrackbar("U-S", "Trackbars", 255, 255, nothing)
cv2.createTrackbar("U-V", "Trackbars", 243, 255, nothing)
font = cv2.FONT_HERSHEY_COMPLEX
while True:
_, frame = cap.read()
hsv = cv2.cvtColor(frame, cv2.COLOR_BGR2HSV)
l_h = cv2.getTrackbarPos("L-H", "Trackbars")
l_s = cv2.getTrackbarPos("L-S", "Trackbars")
l_v = cv2.getTrackbarPos("L-V", "Trackbars")
u_h = cv2.getTrackbarPos("U-H", "Trackbars")
u_s = cv2.getTrackbarPos("U-S", "Trackbars")
u_v = cv2.getTrackbarPos("U-V", "Trackbars")
lower_yellow = np.array([l_h,l_s, l_v])
upper_yellow = np.array([u_h, u_s, u_v])
mask = cv2.inRange(hsv, lower_yellow, upper_yellow)
kernel = np.ones((5, 5), np.uint8)
mask = cv2.erode(mask, kernel)
# Contours detection
if int(cv2.__version__[0]) > 3:
# Opencv 4.x.x
contours, _ = cv2.findContours(mask, cv2.RETR_TREE, cv2.CHAIN_APPROX_SIMPLE)
else:
# Opencv 3.x.x
_, contours, _ = cv2.findContours(mask, cv2.RETR_TREE, cv2.CHAIN_APPROX_SIMPLE)
for cnt in contours:
area = cv2.contourArea(cnt)
approx = cv2.approxPolyDP(cnt, 0.02*cv2.arcLength(cnt, True), True)
x = approx.ravel()[0]
y = approx.ravel()[1]
if area > 400:
cv2.drawContours(frame, [approx], 0, (0, 0, 0), 5)
if len(approx) == 3:
cv2.putText(frame, "Triangle", (x, y), font, 1, (0, 0, 0))
elif len(approx) == 4:
cv2.putText(frame, "Rectangle", (x, y), font, 1, (0, 0, 0))
elif 10 < len(approx) < 20:
cv2.putText(frame, "Circle", (x, y), font, 1, (0, 0, 0))
cv2.imshow("Frame", frame)
cv2.imshow("Mask", mask)
key = cv2.waitKey(1)
if key == 27:
break
cap.release()
cv2.destroyAllWindows()
最佳答案
要执行形状检测,我们可以使用轮廓逼近。假设对象是简单形状,这是一种使用阈值+轮廓近似的方法。等高线近似是基于这样的假设,即曲线可以由一系列短线段近似,这些短线段可用于确定轮廓的形状。例如,三角形具有三个顶点,正方形/矩形具有四个顶点,五边形具有五个顶点,依此类推。
arcLength
计算轮廓的周长,并使用 approxPolyDP
获得实际的轮廓近似值。 import cv2
def detect_shape(c):
# Compute perimeter of contour and perform contour approximation
shape = ""
peri = cv2.arcLength(c, True)
approx = cv2.approxPolyDP(c, 0.04 * peri, True)
# Triangle
if len(approx) == 3:
shape = "triangle"
# Square or rectangle
elif len(approx) == 4:
(x, y, w, h) = cv2.boundingRect(approx)
ar = w / float(h)
# A square will have an aspect ratio that is approximately
# equal to one, otherwise, the shape is a rectangle
shape = "square" if ar >= 0.95 and ar <= 1.05 else "rectangle"
# Pentagon
elif len(approx) == 5:
shape = "pentagon"
# Hexagon
elif len(approx) == 6:
shape = "hexagon"
# Octagon
elif len(approx) == 8:
shape = "octagon"
# Star
elif len(approx) == 10:
shape = "star"
# Otherwise assume as circle or oval
else:
shape = "circle"
return shape
# Load image, grayscale, Otsu's threshold
image = cv2.imread('1.png')
gray = cv2.cvtColor(image, cv2.COLOR_BGR2GRAY)
thresh = cv2.threshold(gray, 0, 255, cv2.THRESH_BINARY_INV + cv2.THRESH_OTSU)[1]
# Find contours and detect shape
cnts = cv2.findContours(thresh, cv2.RETR_EXTERNAL, cv2.CHAIN_APPROX_SIMPLE)
cnts = cnts[0] if len(cnts) == 2 else cnts[1]
for c in cnts:
# Identify shape
shape = detect_shape(c)
# Find centroid and label shape name
M = cv2.moments(c)
cX = int(M["m10"] / M["m00"])
cY = int(M["m01"] / M["m00"])
cv2.putText(image, shape, (cX - 20, cY), cv2.FONT_HERSHEY_SIMPLEX, 0.5, (36,255,12), 2)
cv2.imshow('thresh', thresh)
cv2.imshow('image', image)
cv2.waitKey()
关于python - 如何在Python和Opencv中检测八边形,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/60177653/
我正在为大学制作一个小游戏,我需要在我的元素中添加不同的形状。我说的是三 Angular 形、矩形、五边形、六边形、七边形、八边形……n-gon。我需要所有形状都是凸正多边形并且能够为内部着色。我正在
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