asp.net - 使用 itemtemplate 将列动态添加到 GridView

Question

我想知道如何动态添加列到gridview。 GridView 假设获取用户输入。我知道如何将 itemtemplate 用于特定的列数，但我不知道如何使用 itemtemplate (文本框)字段动态添加列并进行数据绑定(bind)。

Answer 1

您需要创建一个实现 ITemplate 的类，完整代码如下:

public class DynamicTemplateField : ITemplate
{

    public void InstantiateIn(Control container)
    {
        //define the control to be added , i take text box as your need
        TextBox txt1 = new TextBox();
        txt1.ID = "txt1";
        container.Controls.Add(txt1);
    }
}

//Method to bind the Grid View
public void BindData()
{
    TemplateField temp1  = new TemplateField();  //Create instance of Template field
    temp1.HeaderText = "New Dynamic Temp Field"; //Give the header text

    temp1.ItemTemplate = new DynamicTemplateField(); //Set the properties **ItemTemplate** as the instance of DynamicTemplateField class.


    gv.Columns.Add(temp1); //add the instance if template field in columns of grid view

    //Bind the grid  view
    gv.DataSource = [your data source];
    gv.DataBind();

 }

行数据绑定(bind)

protected void gv_RowDataBound(object sender, System.Web.UI.WebControls.GridViewRowEventArgs e)
{
  if(e.Row.RowType == DataControlRowType.DataRow)
   {
      TextBox txt1 = e.Row.FindControl("txt1") as TextBox;
      txt1.Text = e.Row.DataItem["Name"]; //Assign any column value of your datasource
    }

}

.aspx页面

<asp:GridView ID = "gv" runat = "server"  >
    <Columns>

    </Columns>
</asp:GridView>

您可以操作DynamicTemplateField类来添加不同类型的控件