javascript - 通过加载 Controller 保持后退按钮的 Angular ？

Question

根据服务中的逻辑，我会路由到不同的 View 。为了促进服务注入(inject)，我使用加载 Controller 来确定下一步要去哪里。

这非常有效，只是我无法通过加载 Controller “返回”。如何检测后退按钮，或修复我的加载模型以使其更友好？

    .when('/loading', {
                templateUrl: '/app/views/mystuff/loading.html',
                controller: 'LoadingController'
            })

angular.module('app').controller('LoadingController', ['$location', 'WhereService',
    function ($location, WhereService) {
        if (!WhereService.doneWithA()) {
            $location.path('/a');
        }
        else if (!WhereService.doneWithB()) {
            $location.path('/b');
        }
        else {
            location.href = "/myapp/somewhereelseentirely"//this is fine
        }
    }]);

angular.module('app').controller('ALoadingController', ['$location', 'AService',
    function ($location, AService) {
        if (!AService.isDone()) {
            $location.path(AService.currentPath());
        }
        else {
            $location.path('/');//triggers loading controller above
        }
    }]);

Answer 1

听起来你需要$location.replace():

If called, all changes to $location during current $digest will be replacing current history record, instead of adding new one.

https://docs.angularjs.org/api/ng/service/ $地点