powershell - 在 powershell 脚本中添加超时部分

Question

我正在尝试在 30 秒后测试超时。

示例代码:

$a = "y"
$b = "n"
$timeout = New-TimeSpan -Seconds 30
$stopwatch = [System.Diagnostics.Stopwatch]::StartNew()
$stopwatch.Start()
$timeout.Seconds
$stopwatch.elapsed.Seconds
do{

    if($a -eq "n"){
        Write-Host "This block will never run"
        break
    }

    if($stopwatch.elapsed.Seconds -lt $timeout.Seconds){
        Write-Host "Testing this block: Time OUT!!"
        break
    }

}while($a -eq $b)

$stopwatch.Stop()

但是 if block if($stopwatch.elapsed.Seconds -lt $timeout.Seconds) 为真，即使 $stopwatch.elapsed.Seconds 值为 0 且 $timeout.Seconds 值为 30 在循环中完成代码几毫秒而不是 30 秒来打印超时语句。

谁能给我指点以解决这个问题。

Answer 1

一些事情:

• 您不需要这两行:$timeout.Seconds 和 $stopwatch.elapsed.Seconds 在循环之上
• 你的 while 条件应该是 while($a -ne $b)
• 循环内的测试应为 if($stopwatch.elapsed.Seconds -ge $timeout.Seconds)

尝试

$a = "y"
$b = "n"
$timeout = New-TimeSpan -Seconds 30
$stopwatch = [System.Diagnostics.Stopwatch]::new()
$stopwatch.Start()
do {
    if($stopwatch.Elapsed.Seconds -ge $timeout.Seconds){
        Write-Host "Testing this block: Time OUT!!"
        break
    }
    # no timeout, so proceed with what needs to be done here
    # . . .
} while($a -ne $b)  # loop forever unless you set $a equal to $b in the loop somewhere

$stopwatch.Stop()