Bash sed 替换直到行尾

Question

我有以下输入文件:

this is text
     identifier {
         item /directory/file_1234 
some more text 
item /directory/file_1234 other line text
     identifier {
         item /directory/98_76file
other line

我想用 /directory/file_ABC 替换 identifier { 行之后的字符串 item/directory/*

我试过了

cat input | sed ':a;N;$!ba;s/    identifier {\n        item \/directory\/.*$/    identifier {\n        newitem \/directory2\/file_ABC/g'

但它会在第一次出现后删除这些行

this is text
    identifier {
        newitem /directory2/file_ABC

Answer 1

假设你想替换这两个事件，你可以使用这个 sed

$ sed '/identifier {/{N;s~\(.*\n[^[:alpha:]]*\).*~\1newitem /directory/file_ABC~}' input_file
this is text
     identifier {
         newitem /directory/file_ABC
some more text
item /directory/file_1234 other line text
     identifier {
         newitem /directory/file_ABC
other line