angularjs - 使用 DjangoREST + Angular 上传模型 ImageField

Question

我是 REST 新手，并尝试创建简单的应用程序，其中包含一个模型和两个字段 CharField、ImageField。型号:

class Photo(models.Model):

    img = models.ImageField(upload_to='photos/', max_length=254)
    text = models.CharField(max_length=254, blank=True)

序列化器:

class PhotoSerializer(serializers.ModelSerializer):

    class Meta:
        model = Photo
        fields = ('img','text')

浏览次数:

class PhotoViewSet(viewsets.ModelViewSet):

    queryset = Photo.objects.all()
    serializer_class = PhotoSerializer

photo_router = DefaultRouter()
photo_router.register(r'photo', PhotoViewSet)

网址:

urlpatterns = [
    url(r'^admin/', admin.site.urls),
    url(r'^api/', include(photo_router.urls)),]

POST 和 GET 在 /api/photo/
中运行良好我之前问过类似的问题，我确信问题出在前端，使用 AngularJS，我也是第一次使用 AngularJS。但我现在想，可能是我的服务器应用程序有问题。
Angular 代码:

var app = angular.module('myApp', ['ngRoute', 'angularFileUpload']);

app.config(function ($routeProvider) {

    $routeProvider
        .when('/', {
            templateUrl: 'http://127.0.0.1:8000/static/js/angular/templates/home.html'
    })
});
app.config(['$httpProvider', function($httpProvider) {
    $httpProvider.defaults.xsrfCookieName = 'csrftoken';
    $httpProvider.defaults.xsrfHeaderName = 'X-CSRFToken';
}]);

GET Controller 运行良好，我收到了所有图像:

app.controller('getController', ['$scope', '$http', function($scope, $http){
    $http.get('/api/photo/').success(function(data){
        $scope.photos = data;
    }).error(function(data) {
        $scope.photos = data;
    });
}]);

对于文件上传，我使用 this guide
这是指南中的代码:

app.directive('fileModel', ['$parse', function ($parse) {
return {
    restrict: 'A',
    link: function(scope, element, attrs) {
        var model = $parse(attrs.fileModel);
        var modelSetter = model.assign;

        element.bind('change', function(){
            scope.$apply(function(){
                modelSetter(scope, element[0].files[0]);
            });
        });
    }
};
}]);
app.service('fileUpload', ['$http', function ($http) {
    this.uploadFileToUrl = function(file, uploadUrl){
        var fd = new FormData();
        fd.append('file', file);
        $http.post(uploadUrl, fd, {
            transformRequest: angular.identity,
            headers: {'Content-Type': undefined}
        })
        .success(function(){
        })
        .error(function(){
        });
    }
}]);
app.controller('myCtrl', ['$scope', 'fileUpload', function($scope,     fileUpload){

    $scope.uploadFile = function(){
        var file = $scope.myFile;
        console.log('file is ' );
        console.dir(file);
        var uploadUrl = "/api/photo/";
        fileUpload.uploadFileToUrl(file, uploadUrl);
    };

}]);

html代码:

<div ng-controller = "myCtrl">
    <input type="file" file-model="myFile"/>
    <button ng-click="uploadFile()">upload me</button>
</div>

当我通过此表单上传文件时，我有:

POST http://127.0.0.1:8000/api/photo/ 400 (Bad Request)
in responce:
img: ["No file was submitted."]

请至少帮助理解我的问题出在哪里，在我的 REST 上还是在 Angular 上。我该如何调试这个？我花了一整天的时间试图找到解决方案。我想我显然不明白 REST api 需要是什么样子。
UPD
我正在尝试使用ng-file-upload并且仍然有 400 响应状态。
我认为序列化程序有问题，我覆盖了 View 中的 POST 方法，但我认为我做错了:

class PhotoViewSet(viewsets.ModelViewSet):  
    queryset = Photo.objects.all()
    serializer_class = PhotoSerializer

    def post(self, request, format=None):
        serializer = PhotoSerializer(data=request.DATA)
        if serializer.is_valid():
            serializer.save()
            return Response(serializer.data,  status=status.HTTP_201_CREATED)
        return Response(serializer.errors, status=status.HTTP_400_BAD_REQUEST)

以下是来自网络工具的完整请求数据:

General
Request URL:http://127.0.0.1:8000/api/photo/
Request Method:POST
Status Code:400 Bad Request
Remote Address:127.0.0.1:8000
Response Headers
Allow:GET, POST, HEAD, OPTIONS
Content-Type:application/json
Date:Wed, 09 Mar 2016 14:46:44 GMT
Server:WSGIServer/0.2 CPython/3.4.3
Vary:Accept, Cookie
X-Frame-Options:SAMEORIGIN
Request Headers
Accept:application/json, text/plain, /
Accept-Encoding:gzip, deflate
Accept-Language:ru-RU,ru;q=0.8,en-US;q=0.6,en;q=0.4
Connection:keep-alive
Content-Length:16635
Content-Type:multipart/form-data; boundary=---- WebKitFormBoundarytci4JfMISlMXwzFw
Cookie:sessionid=f5nyqdclupgi44zyqbmo3gkenum9k0cj; csrftoken=E0DuVDs5KrV0rSMuD5wC86RPO0QP4AgT
Host:127.0.0.1:8000
Origin:http://127.0.0.1:8000
Referer:http://127.0.0.1:8000/
User-Agent:Mozilla/5.0 (X11; Linux x86_64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/47.0.2526.106 Safari/537.36
X-CSRFToken:E0DuVDs5KrV0rSMuD5wC86RPO0QP4AgT
Request Payload
------WebKitFormBoundarytci4JfMISlMXwzFw
Content-Disposition: form-data; name="file"; filename="2.jpg"
Content-Type: image/jpeg
------WebKitFormBoundarytci4JfMISlMXwzFw--

Answer 1

查看页面 Django Rest Framework File Upload 上提供的示例:

您需要添加相关的 parser_classes在 View 中，还重写 perform_create 函数以从 POST 数据获取 file:

class PhotoViewSet(viewsets.ModelViewSet):

    queryset = Photo.objects.all()
    serializer_class = PhotoSerializer
    parser_classes = (MultiPartParser, FormParser,)

    def perform_create(self, serializer):
        serializer.save(img=self.request.data.get('img'))
        # do note that at this time `text` information is not available

自从我们发布 FormData 以来，我们使用以下解析器 ( link ):

parser_classes = (MultiPartParser, FormParser,)  

此外，请注意 serializer.is_valid() 会抛出错误，因为它没有获取发布数据中的 img 字段。您需要设置 img 而不是 file 字段:

fd.append('img', file);