sql - 如何在 SQL Server 中显示日期名称？

Question

我在 SQL 服务器上有一个查询

我想显示如下:

CDATE      | CDAY
2019-04-01 | Monday
2019-04-02 | Tuesday
...        | ......
2019-04-30 | Tuesday

但是我发现错误如下:

Conversion failed when converting date and/or time from character string.

如果有人可以帮忙

DECLARE @V_DATE DATE = GETDATE()

;WITH CTE_DATE AS (
        SELECT  DATEADD(dd,-(DAY(@V_DATE)-1),@V_DATE) CDATE,
        DATENAME(dw, CONVERT(varchar, DATEADD(dd,-(DAY(@V_DATE)-1),@V_DATE))) CDAY
        UNION ALL
        SELECT  DATEADD(dd,1,CDATE),
        DATENAME(dw, CONVERT(varchar, DATEADD(dw,1,CDAY)))
        FROM    CTE_DATE
        WHERE   DATEADD(dd,1,CDATE) <= DATEADD(dd,-(DAY(DATEADD(mm,1,CDATE))),DATEADD(mm,1,CDATE))

    )
    SELECT * FROM CTE_DATE

Answer 1

您很快就可以使用datename()函数(自 v.2008 起使用)

  select datename( weekday, getdate() ) as day

  day
  ------
  Friday  -- > "for today(2019-04-26)"

Demo

或如您的情况:

with t(cdate) as
(
 select '2019-04-01' union all
 select '2019-04-02' union all
 select '2019-04-30'    
)    
select cdate, datename( weekday, cdate  ) as cday
  from t;

+----------+-------+
| cdate    | cday  |
+----------+-------+
|2019-04-01|Monday |
|2019-04-02|Tuesday|
|2019-04-30|Tuesday|
+----------+-------+