JavaScript - 如何通过查找值来查找对象属性

Question

我有一个带有属性和子属性的对象，我需要找到这些属性和子属性以查找它们是否包含特定值。

这是我的data对象的示例:

var data = [
{ 
    value: 'Orlando International Airport (MCO)', 
    data: { 
            category: 'Airport',
            address: '1 Jeff Fuqua Blvd., Orlando, FL',
            airport: 'MCO',
            location: 'Orlando'
          } 
},
{ 
    value: 'Orlando Sanford International Airport (SFB)', 
    data: { 
            category: 'Airport',
            address: '1200 Red Cleveland Blvd., Sanford, FL',
            airport: 'SFB',
            location: 'Orlando'
          } 
},
{ 
    value: 'Port Canaveral Cruise Terminal', 
    data: { 
            category: 'Cruise Terminal',
            address: 'Port Canaveral, FL',
            airport: '',
            location: 'Port Canaveral'
          } 
},
{ 
    value: 'Baymont Inn & Suites Florida Mall/Orlando', 
    data: { 
            category: 'Hotel',
            address: '8820 S Orange Blossom Trail, Orlando, FL',
            airport: '',
            location: 'Orlando'
          } 
},

问题:我需要一个函数，如果满足则返回 true

location1 == 'Port Canaveral' && location2 == 'Orlando'

如果则为假

(location1 == 'Orlando' && location2 == 'Orlando') || (location1 == 'Port Canaveral' && location2 == 'Port Canaveral')

但我只知道应该确定相应位置的“值”属性。我希望真正擅长使用 JavaScript 对象的人可以在这里帮助我。

更新1:简而言之，我需要一个与此类似的函数:

function locations_different(string1, string2) {
    i1 = data.value.indexOf(string1);
    location1 = data[i1].data.location;

    i2 = data.value.indexOf(string2);
    location2 = data[i2].data.location;

    return ((location1 == 'Port Canaveral' && location2 == 'Orlando') && !((location1 == 'Orlando' && location2 == 'Orlando') || (location1 == 'Port Canaveral' && location2 == 'Port Canaveral')));
}

更新 2:这是一个不起作用的 jsfiddle:http://jsfiddle.net/p1n20tzk/

更新 3:这是一个有效的更新(感谢 @james-k 启动它)http://jsfiddle.net/edj0qvu0/

Answer 1

    Object.byString = function(o, s) {
    s = s.replace(/\[(\w+)\]/g, '.$1'); // convert indexes to properties
    s = s.replace(/^\./, '');           // strip a leading dot
    var a = s.split('.');
    for (var i = 0, n = a.length; i < n; ++i) {
        var k = a[i];
        if (k in o) {
            o = o[k];
        } else {
            return;
        }
    }
    return o;

if(Object.byString(data, 'valueString.location') == 'Port Canaveral'){
   return true;
}else{
   return false;
}