grails - 如何在获取 child 的信息时获取 parent 的身份证-Grails？

Question

如何根据显示的statusItem(用户的子代)访问用户的名字和姓氏。

class UserAccount implements Serializable {


static transients = ['pass','passConfirm','familyPicTmp', 'familyPicTmpFilename', 'photoTmp', 'photoTmpFilename']
static hasMany = [authorities: Authorisation, memberships:FamilyMembership, progenitorIwi:Family,  politicItems:PoliticItem,
    relationships:Relationship, , agents:UserAccount, media:UserMedia, status:Status]
static mappedBy = [ progenitorIwi:"progenitor",relationships:'relationTo', relationships:'userAccount']
static fetchMode = [memberships:FetchMode.JOIN, agents:FetchMode.JOIN]
static mapping = {
    memberships(lazy:false)
    agents(lazy:false)
}

static belongsTo = [Authorisation]

状态域

class Status {
  static belongsTo = [userAccount:UserAccount]
  def String statusMessage
  Date dateCreated
  Date lastUpdated
  def String statusType

政治 Realm

class PoliticItem {

    SystemEntity politicItemName
    UserAccount userAccount

    def String politicItemValue
    def boolean shared = false
    Date dateCreated
    Date lastUpdated

我们如何才能将属于所有状态的所有用户加载到政治 View 中？

Answer 1

我仍然不确定您不知道哪一部分。假设userAccount具有firstName和lastName字段以从状态访问它们，请尝试以下操作:
status是Status类的实例。您需要从中删除userAccount的那个。

status.userAccount.firstName

要么

status.userAccount.lastName