java - 消除 lambda 中函数接口(interface)的歧义

Question

假设这样:

ExecutorService service = ...;

// somewhere in the code the executorService is used this way:
service.submit(() -> { ... });

lambda 表达式默认为Callable。
有没有办法让它实例化一个Runnable？

感谢您的帮助。

Answer 1

您可以将其声明为 Runnable，或使用强制转换:

Runnable r = () -> { ... };
executorService.submit(r);

或

executorService.submit((Runnable) () -> { ... });