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javascript - 使用新数据重新渲染 D3 强制定向布局

转载 作者:行者123 更新时间:2023-12-02 15:20:22 27 4
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我正在使用 d3 力定向图形布局来显示一些数据。当我双击节点旁边的名称时,我想用新数据重新渲染图形。我找到了simular question on StackOverflow ,但这对我来说并没有真正发挥作用。关键似乎是我也在调用的 force.start(); 方法。这是我到目前为止编写的代码。它被缩短到绝对最小值。

var height =  600;
var width = 800;
var color = d3.scale.category20();
var svg = d3.select('body').append('svg').attr('width', width).attr('height',
height).attr("pointer-events", "all").append("g").append("g");
svg.append("rect").attr("class", "overlay").attr("width", width).attr("height", height);

function draw(json) {
var force = self.force = d3.layout.force()
.nodes(json.nodes)
.links(json.links)
.gravity(.05)
.distance(150)
.charge(-100)
.size([width, height])
.start();

var link = svg.selectAll(".link").data(json.links).enter().append("line")
.attr("class", "link").style("stroke-width", 1);

var gnodes = svg.selectAll('g.gnode').data(json.nodes).enter().append('g').classed('gnode', true);


var node = gnodes.append("circle").attr("class", "node").attr("r", 5)
.style("fill", function(d) {
return color(d.group);
});

var labels = gnodes.append("text").text(function(d) {
return d.name;
}).attr("dx", 5).attr("dy", ".35em").on('dblclick', function(d){
redraw();
});
gnodes.selectAll("circle.node").on("click", function() {
d3.select(this);
});
force.on("tick", tick);

function tick() {
link.attr("x1", function(d) { return d.source.x; })
.attr("y1", function(d) { return d.source.y; })
.attr("x2", function(d) { return d.target.x; })
.attr("y2", function(d) { return d.target.y; });
gnodes.attr("transform", function(d) { return "translate(" + d.x + "," + d.y + ")"; });
}
force.start();
};


function invoke(){
inputString = {
"nodes":[
{"concept":"man","name":"John","id":0,"shortname":"","group":2},
{"concept":"woman","name":"Mia","id":1,"shortname":"","group":6},
{"concept":"child","name":"Harry","id":2,"shortname":"","group":7},
{"concept":"child","name":"Sally","id":3,"shortname":"","group":7},
{"concept":"old women","name":"Judith","id":4,"shortname":"","group":8},
{"concept":"old man","name":"Lionel","id":5,"shortname":"","group":7}
],
"links":[
{"source":0,"target":1,"relation":"married"},
{"source":0,"target":2,"relation":"father"},
{"source":1,"target":2,"relation":"mother"},
{"source":0,"target":3,"relation":"father"},
{"source":1,"target":3,"relation":"mother"},
{"source":5,"target":2,"relation":"grandfather"},
{"source":5,"target":3,"relation":"grandfather"},
{"source":4,"target":2,"relation":"grandmother"},
{"source":4,"target":3,"relation":"grandmother"},
{"source":5,"target":1,"relation":"father"},
{"source":4,"target":1,"relation":"mother"}
]
};
draw(inputString);
}

function redraw(){
inputString = {
"nodes":[
{"concept":"man","name":"Alan","id":0,"shortname":"","group":2},
{"concept":"woman","name":"Judith","id":1,"shortname":"","group":6},
{"concept":"child","name":"Jack","id":2,"shortname":"","group":7},
{"concept":"child","name":"Rosana","id":3,"shortname":"","group":7},
{"concept":"old women","name":"Evelyn","id":4,"shortname":"","group":8},
{"concept":"old man","name":"Charlie","id":5,"shortname":"","group":7}
],
"links":[
{"source":0,"target":1,"relation":"married"},
{"source":0,"target":2,"relation":"father"},
{"source":1,"target":2,"relation":"mother"},
{"source":0,"target":3,"relation":"father"},
{"source":1,"target":3,"relation":"mother"},
{"source":5,"target":2,"relation":"grandfather"},
{"source":5,"target":3,"relation":"grandfather"},
{"source":4,"target":2,"relation":"grandmother"},
{"source":4,"target":3,"relation":"grandmother"},
{"source":5,"target":1,"relation":"father"},
{"source":4,"target":1,"relation":"mother"}
]
};
draw(inputString);
}

var inputString = undefined;

invoke();

调用双击行为的部分在这里:

var labels = gnodes.append("text").text(function(d) {
return d.name;
}).attr("dx", 5).attr("dy", ".35em").on('dblclick', function(d){
redraw();
});

redraw(); 有新数据,应该只调用我的函数来再次绘制图形。对我来说,双击节点似乎只能工作一次。即使他们也绘制旧数据。我准备了一个fiddle demo ,以及我迄今为止所拥有的一切。
我在重新渲染图表时做错了什么?

最佳答案

在绘制函数中渲染之前,您需要删除节点和链接。

function draw(json) {
svg.selectAll(".link").remove();//add this to remove the links
svg.selectAll(".gnode").remove();//add this to remove the nodes
...your old code.

工作代码here .

关于javascript - 使用新数据重新渲染 D3 强制定向布局,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/34130568/

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